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3 years ago

What is the answer for 2x+34

Mathematics

2 answers:

diamong [38]3 years ago

6 0

Answer:

Step-by-step explanation:

Akimi4 [234]3 years ago

5 0

2(x + 17)

simplify or factorize

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L thought that maybe it was *C* but I just want to be sure of my answer

ioda

You are right, it's C. I checked in geogebra bro/girly/dude.

Hope this helps !

Photon

7 0

3 years ago

235 people are at RSM summer camp. There are 35 more boys than girls, and 70 fewer adults than girls. How many people of each gr

makkiz [27]

Answer:

The number of girls are 90 girls

The number of boys are 125 boys

The number of adults are 20 adults

There are 90 girls, 125 boys and 20 adults at the camp

Step-by-step explanation:

The total number of people is given as 235 people

The number of boys = 35 + The number of girls

The number of adults = The number of girls - 70

Let the total number of girls = G

Therefore, we have;

The number of boys = 35 + G

The number of adults = G - 70

The total number of persons = The number of boys + The number of adults + The number of girls

Therefore;

235 = The number of boys + The number of adults + The number of girls

Which gives;

235 = 35 + G + G - 70 + G = 3·G - 35

235 = 3·G - 35

3·G - 35 = 235

3·G = 235 + 35 = 270

G = 270/3 = 90

The number of girls = 90

The number of boys = 35 + The number of girls = 35 + 90 = 125

The number of boys = 125

The number of adults = The number of girls - 70 = 90 - 70 = 20

The number of adults = 20.

8 0

3 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

4 years ago

Brianna walks 5/12 of a mile to school everyday. So far she has walked 1/4 of a mile. How much of her walk is left?

zaharov [31]

5/12- 3/12= 2/12 so 1/6 of a mile

4 0

3 years ago

△ABC∼△DEF , △ABC has a height of 14 centimeters, and △DEF has a height of 6 centimeters. What is the ratio of the area of △ABC t

Kamila [148]

Since triangle ABC is similar to triangle DEF then the ratio of the corresponding sides is constant.
The ratio of the corresponding lengths is referred to as the linear scale factor.
Considering the heights of the two triangles;
L.S.F = 14/6
= 7/3
The ratio in area (A.S.F) is given by (L.S.F)²
Therefore, A.S.F = (7/3)² = 49/9
Thus te ratio of the area of triangle ABC to DEF is 49:9

8 0

4 years ago

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