Answer:
System has equal number of unknowns and equations.
Manipulation easily yielded expressions for 4 of the 7 unknowns.
However it seems that the remaining 3 unknowns x,y,z are not fixed by the equations. Different combinations (x0,y0,z0) seem possible without violating the system equations.
Is this possible, or did I most probably make a mistake in counting degrees of freedom?
Step-by-step explanation:
She has 445 left after the bear ate some so
21 × 12 = 252
252 + 445 = 697 acorns
she should maybe bother the bear so he can't hibernate, or steal his food so he knows what it's like
Answer:
The chances of landing on red are 1 in 4, or one fourth. This problem asked us to find some probabilities involving a spinner
<h2>
<em><u>I </u></em><em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> </u></em><em><u> </u></em><em><u>please</u></em><em><u> mark</u></em><em><u> me</u></em><em><u> as</u></em><em><u> brainlist</u></em><em><u> </u></em></h2>
Prime Factors of 60: 2,3, and 5
Prime Factors of 140: 2,5 and 7
All mental math no work needed.
B - (5 x 8) - 3
A is adding 3, not subtracting.
C is basically 5 squared.
D is 5 lots of 11.
