The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
Answer:
I don't understand the array of numbers as written in the question.
Step-by-step explanation:
See attached image
Answer:
the answer is 92 bags.
167x11=1837
1837÷20=91.85....or 92 bags
Answer:
350
Step-by-step explanation:
you just have to subtract ibthink
Answer:
2 times
Step-by-step explanation:
Well let's first graph the quadratic equation,
Look at the image below ↓
By looking at the image below we can tell that the graph touches the x axis 2 times at,
<u>(-1,0)</u>
<u>(1 1/3,0)</u>
<em />
<em>Thus,</em>
<em>the parabola touches the x axis twice.</em>
<em />
<em>Hope this helps :)</em>