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Gnom [1K]
3 years ago
12

Special right triangles Find j Thank you for any help ;)

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0
Given b=21 and ∠β=60°,
a = 12.12436 = 7√3
j = 24.24871 = 14√3
∠α = 30° = 0.5236 rad = π/6
h = 10.5
area = 127.30573 = 147√3/2
perimeter = 57.37307
inradius = 4.43782
circumradius = 12.12436 = 7√3

Answer is
j = 24.24871 = 14√3
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mamaluj [8]

Hey there!!

The given equation :

... 5y ( 2y - 3 ) + ( 2y - 3 )

Let's write this as ...

... 5y ( 2y - 3 ) + 1 ( 2y - 3 )

Now, if we take ( 2y - 3 ) as a common term, we get...

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Given:

The given quadratic equation is:

12a^2+9a+7=0

To find:

The solution for the given quadratic equation in simplest form by using the quadratic formula.

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x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

The given quadratic equation is:

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