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shepuryov [24]
3 years ago
13

Please help me i will mark you brainliest

Mathematics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

it will be c

Step-by-step explanation:

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1/2 times -1/4 PLEASEEEEEE
zysi [14]

Answer:-0.125 or 1/8

Step-by-step explanation: :)

3 0
3 years ago
Read 2 more answers
Show all the steps!<br><br>3+2x=13-3x
Goshia [24]

Answer:

x=2

Step-by-step explanation:

3+2x=13-3x

 +3x      +3x

3+5x=13

-3      -3

5x=10

/5    /5

x=2

Hope this helps! :D

7 0
3 years ago
Read 2 more answers
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
Which expression gives the same result as shown problem?
sineoko [7]
The first choice gives you the same result. The factor of 5 can be removed to the outside of the summation symbol.

5\sum\limits_{i=0}^{4}{\left(\dfrac{1}{3}\right)^{i}}
8 0
3 years ago
Following a major renovation, the monthly population of patrons visiting a theme park grew according to the model P=3,000(1.21)^
babymother [125]
P= 3000 (1.21)^t,  t= time in months

1 year = 12 months, and therefore, 1 month = 1/12 years

The equation showing yearly population growth changes to;

P=3000 (1.21)^t/12

The  correct answer is equation [1].
8 0
3 years ago
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