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Serjik [45]
3 years ago
13

Secants ⎯⎯⎯⎯⎯⎯⎯⎯⎯ and ⎯⎯⎯⎯⎯⎯⎯⎯ intersect at point T in the interior of a circle. The measure of ∠ is 61.99°. The measure of ⏜ is

70.80°. Determine the measure of ⏜

Mathematics
1 answer:
kiruha [24]3 years ago
4 0

Answer:

PR = 53.18°

Step-by-step explanation:

Given:

m<PTR = 61.99°

arc SQ = 70.80°

Required:

Measure of arc PR

Solution:

Based on the theorem of angles with vertex inside the circle and intercepted arcs, we would have the following equation:

m<PTR = ½(PR + SQ)

Plug in the values

61.99 = ½(PR + 70.80)

Multiply both sides by 2

2*61.99 = PR + 70.80

123.98 = PR + 70.80

123.98 - 70.80 = PR

53.18 = PR

PR = 53.18°

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nikitadnepr [17]

Answer:

717,051

seven hundred seventeen thousand, fifty-one

Step-by-step explanation:

8 0
3 years ago
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There are two pieces of wires, each of length 66 cm. One wire is bent into a square and the other wire is bent into a circle. Fi
antiseptic1488 [7]

Answer:

Area of Circle  = 346.5 cm².

Area of square = 272.25 cm ² .

Step-by-step explanation:

So , 2πR = 66

2 × 22 / 7 × R = 66

R comes out is 21/2 cm .

Area of Circle = 22/7 × 21/2 × 21/2 = 33×21/2

= 693 / 2 = 346.5 cm².

If bent into the shape of a square ;

4 a = 66

a = 33/2 . ( Side of a square )

Area of square = a ² = 33×33/4 = 1089/4

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6 0
2 years ago
A circle has a circumference of 113.04. What is the diameter of the circle?
Alekssandra [29.7K]

Answer:

56.52

Step-by-step explanation:

because the circumference is double the diameter and the circumference is 113.04 so half of that is 56.52

8 0
4 years ago
A student has a class that is supposed to end at 9:00am and another that is supposed to begin at 9:10am. Suppose the actual endi
never [62]

Answer:

0.8340

Step-by-step explanation:

The aim of this question is to find the probability that the student makes it to the second class prior to when the lecture commences.

Provided that A, B, and C are independent of each other from the full complete question.

Then; we want P(A + C < B)

So A \sim N (2, 1.5)

B \sim N (10, 1)

C \sim N (6, 1)

P(A + C - B < 0)

Since they are normally distributed( i.e. A + C - B)

Then;

E(A + C -B) = E(A) + E(C) - (B)

E(A + C -B) = 2 - 10 + 6

E(A + C -B) =  -2

Var(A+C -B) = Var(A) + Var (B) + Var (C)

Var(A + C -B) = (1.5)² + (1)² + (1)²

Var(A + C -B) = 4.25

The standard deviation = \sqrt{4.25}

The standard deviation = 2.06155

P(A+C-B) = p \Big (Z < \dfrac{0-(-2)}{2.06155} \Big )

P(A+C-B) = p \Big (Z \le 0.97014  \Big )

\mathbf{P(A+C-B) = 0.8340}

7 0
3 years ago
Helllllpppp I need to find the area
Masja [62]
Divide it into two squares.
The first square is just (1)1, which equals 1 cm^2, and add that to the second square, which is just (2)2, which equals 4, so 1+4=5 cm^2.
3 0
4 years ago
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