Y=x+1 Y=2x-5 How many solutions does it have

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Alja [10]

The answer to the question

3 0

2 years ago

If q(x)=7x^2-1 find q(-9)

liq [111]

For this, we are just going to plug in -9 for every x and then solve the equation:

$q(x)=7x^{2} -1$

$q(-9)=7(-9)^{2} -1$

$q(-9)=7(81)-1$

$q(-9)=566$

Now we know that q(-9) is equal to 566.

3 0

2 years ago

A new dental bondlng agent. When bonding teeth, orthodontists must maintain a dry field. A new bonding adhesive(called "Smartbon

Gemiola [76]

Answer:

(a) H₀: μ ≥ 5.70 vs. Hₐ:μ < 5.70

(b) The rejection region is (t₀.₀₁,₉ ≤ -2.821).

(c) The value of the test statistic is -4.33.

(d) The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

Step-by-step explanation:

A hypothesis test should be conducted to determine that the if the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(a)

The hypothesis is:

H₀: The true mean breaking strength of the new bonding adhesive is not less than 5.70 Mpa, i.e. μ ≥ 5.70.

Hₐ: The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa, i.e. μ < 5.70.

(b)

The alternate hypothesis indicates that the hypothesis test is left-tailed.

The rejection region for the left tailed test will be towards the lower tail of the t-distribution curve.

The significance level of the test is: α = 0.01.

The critical value is:

$t_{\alpha ,(n-1)}=t_{0.01,(10-1)}=t_{0.01,9}$

Use the t-table for the critical value.

$t_{\alpha ,(n-1)}=t_{0.01,9}=-2.821$

Since rejection region is in the lower tail the critical value will be negative.

Thus, the rejection region is (t₀.₀₁,₉ ≤ -2.821).

(c)

The test statistic value is:

$t=\frac{\bar x-\mu}{s/\sqrt{n}}$

Given:

$\bar x=5.07\\s=0.46\\n=10\\\mu=5.70$

Compute the value of the t-statistic as follows:

$t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{5.07-5.70}{0.46/\sqrt{10}} =-4.33$

The value of the test statistic is -4.33.

(d)

The value of the test is less than the critical value.

$t=-4.33$

This implies that the test statistic lies in the rejection region.

Hence the null hypothesis will be rejected at 1% significance level.

Conclusion:

As the null hypothesis is rejected it can be concluded that the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(e)

The conditions required for the t-test for single mean to be valid is:

The data should be continuous.
The parent population should be normally distributed.
The sample should be randomly selected.

5 0

2 years ago

A used-boat dealership buys a boat for $2800 and then sells it for $4000. What is the percent increase?

Rudik [331]

Answer:

Step-by-step explanation:

percent increase = increase divided by original number x 100

increase is the difference between the two numbers...

new number - original number.....4000 - 2800 = 1200

percent increase = (1200 / 2800) x 100

= 0.42857 (round to .4286) x 100

= 42.86 %.....if you need it rounded to the nearest percent, it would be 43% increase

6 0

2 years ago

Graph of function F(t) close as possible the value of F(-2)

scoundrel [369]

Answer:

look at the explanation

Step-by-step explanation:

in order to create a f(-2) you would need to know either a table of values or an equation to plug values into . . .saying a function of -2 does not really help, sorry

6 0

2 years ago

Y=x+1Y=2x-5How many solutions does it have