Can someone help me with this? Right answer gets brainliest!! :)
2 answers:
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Answer:
Probability that a smoker has lung disease = 0.2132
Step-by-step explanation:
Let L = event that % of population having lung disease, P(L) = 0.07
So,% of population not having lung disease, P(L') = 1 - P(L) = 1 - 0.07 = 0.93
S = event that person is smoker
% of population that are smokers given they are having lung disease, P(S/L) = 0.90
% of population that are smokers given they are not having lung disease, P(S/L') = 0.25
We know that, conditional probability formula is given by;
P(S/L) =
= P(S/L) * P(L)
= 0.90 * 0.07 = 0.063
So, = 0.063 .
Now, probability that a smoker has lung disease is given by = P(L/S)
P(L/S) =
P(S) = P(S/L) * P(L) + P(S/L') * P(L')
= 0.90 * 0.07 + 0.25 * 0.93 = 0.2955
Therefore, P(L/S) = = 0.2132
Hence, probability that a smoker has lung disease is 0.2132 .
Answer:
Step-by-step explanation:
The continuous compound formula is
where P is the principle or starting value, r is the growth rate in decimal form, and t is the time in years. For us:
which would probably round to just 3848 people.