Answer:
The answer to the question provided is
Answer:
Option (1)
Step-by-step explanation:
Lines given in the graph represent the piecewise function,
We will find the domain of the given pieces in each quadrant of the graph.
For a line in quadrant 2,
Domain (set of x-values) → [-4, -2]
For second line in the same quadrant,
Domain : [-1, 0]
For a line in quadrant 4,
Domain : [1, 3]
Therefore, Option (1) is the correct option,
Option (1). 1 ≤ x ≤ 3
Answer:
The sentence which accurately completes the proof is: "Triangles BCA and DAC are congruent according to the Angle-Side-Angle (ASA) Theorem." ⇒ 2nd answer
Step-by-step explanation:
Let us revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles and one side in the 2nd Δ
- HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right Δ
In Parallelogram ABCD
∵ Segment AB is parallel to segment DC
∵ Segment BC is parallel to segment AD
- Construct diagonal A C with a straightedge
In Δs BCA and DAC
∵ AC is congruent to itself ⇒ Reflexive Property of Equality
∵ ∠BAC and ∠DCA are congruent ⇒ Alternate Interior Angles
∵ ∠BCA and ∠DAC are congruent ⇒ Alternate Interior Angles
- AC is joining the congruent angles
∴ Δ BCA is congruent to Δ DAC by ASA Theorem of congruence
By CPCTC
∴ AB is congruent to CD
∴ BC is congruent to DA
The sentence which accurately completes the proof is: "Triangles BCA and DAC are congruent according to the Angle-Side-Angle (ASA) Theorem."
Answer:
{0}
Step-by-step explanation:
{0} is not because 0 is not an element of set {1, 2, 3}
The null set is a subset of every set, so Ø is.
A set is a subset of itself.
