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Sophie [7]
4 years ago
8

Liz is collecting all 24 dolls in a special collection. So far, she has received 6 of the dolls for her birthdays and special oc

casions. What percentage of the collection does Liz have so far?
Mathematics
1 answer:
Oduvanchick [21]4 years ago
8 0
24 -6=18 Liz need 18 solos too make 24 total
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Please help me out with this!! No joke answers!
Oxana [17]

Answer:

13 protons

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Step-by-step explanation:

protons and electrons are mostly always the same

7 0
3 years ago
Please help me asap!​
pickupchik [31]
“d”

you know b cannot work because the x is raised to the x^2 which would be a diff graph

a does not work because -x^3 the graph would be flipped

c is incorrect because the five is in the negative region; not positive
7 0
3 years ago
HELPPPP PLZZZZZ
zheka24 [161]

Answer:

  see below

Step-by-step explanation:

For the HL theorem to be applicable, the hypotenuses must be the same length:

  x+3 = y-1

and the marked legs must be the same length:

  y-3 = 2x-1

__

Recognizing y-3 = (y-1) -2, we can substitute into the second equation using the first equation:

  (y -1) -2 = 2x -1

  (x +3) -2 = 2x -1 . . . substitute for y-1

  2 = x . . . . . . . . . . add 1-x to both sides

Then the first equation tells us ...

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The values of x and y are ...

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5 0
3 years ago
two towers labeled Tower A and Tower B some distance apart and a fire image at a certain distance from both towers Towers A and
astra-53 [7]

Answer:

7.0 mi

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle C

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

substitute the given values

42^o+64^o+C=180^o\\C=180^o-106^o=74^o

step 2

Find the measure of a

Applying the law of sines

\frac{c}{sin(C)}=\frac{a}{sin(A)}

substitute the given values

\frac{10}{sin(74^o)}=\frac{a}{sin(42^o)}

solve for a

a=\frac{10}{sin(74^o)}sin(42^o)\\a=7.0\ mi

8 0
3 years ago
Read 2 more answers
The product of v and 5 is less than 43
igor_vitrenko [27]
I think it’s v • 5 < 43
5 0
3 years ago
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