9514 1404 393
Answer:
970
Step-by-step explanation:
It turns out that the radical terms cancel, so the result is an integer. You can find the integer value using your calculator. It is ...
(5 +2√6)³ +1/(5 +2√6)³ = 970
_____
The cube of 'a' is ...
(5+2√6)³ = 5³ +3·5²·2√6 +3·5·(2√6)² +(2√6)³
= 125 +3·50√6 +3·120 +48√6
a³ = 485 +198√6
The reciprocal of this is ...
b³ = 1/a³ = 1/(485 +198√6) = (485 -198√6)/(485² -6·198²) = (485 -198√6)/1
b³ = 485 -198√6
Then the sum is ...
a³ +b³ = (485 +198√6) +(485 -198√6) = 970
How you do this is using the formula speed = distance/time. So this is 100/5 which is 20 meters a second. Using the conversion factor (can google "20 meters per second is how many mile") 20 meters a second = 44.7 miles per hour.
In conclusion, the answer you're looking for is D. 44.7 miles per hour.
Multiply 10 times 5 then divide it by 4
9514 1404 393
Answer:
-0.16
Step-by-step explanation:
The 'a' value can be found by looking at the difference between the y-value of a point 1 unit from the vertex, and the y-value of the vertex.
Here, that is a negative fraction of a unit. If we assume the value is a rational number that can be accurately determined from this graph, then we can find it by looking for a point where the graph crosses a grid intersection. It looks like such grid points are (-7, 0) and (3, 0). The vertex is apparently (-2, 4), so the vertex form of the equation is ...
y = a(x +2)^2 +4
Using the point (3, 0), we have ...
0 = a(3 +2)^2 +4 . . . . . fill in the values of x and y
-4 = 25a . . . . . . . . . . subtract 4; next, divide by 25
a = -4/25 = -0.16
The perimeter of the first figure is 34 cm and the area is 64 cm².
The perimeter of the second figure is 38 cm and the area is 60 cm².
The perimeter of the third figure is 30 cm and the area is 36 cm².
The perimeter of the fourth figure is 72 cm and the area is 200 cm².
The perimeter of the fifth figure is 30 cm and the area is 36 cm².
To find the perimeter of each, we add the area of all sides. For the first figure, the missing sides are 1 cm and 6 cm. To find the area, we have two rectangles whose dimensions are 6x10 and 1x4.
For the second figure, the missing sides are 4 cm and 3 cm. To find the area, we have two rectangles whose dimensions are 4x12 and 3x4.
For the third figure, the missing sides are 3 cm, 3 cm and 8 cm. To find the area, we have two rectangles whose dimensions are 4x3 and 3x8.
For the fourth figure, the missing sides are 10 cm, 10 cm, 6 cm and 6 cm. To find the area, we have two squares whose dimensions are 10x10.
For the fifth figure, the missing sides are 3 cm and 9 cm. To find the area, we have two rectangles whose dimensions are 3x6 and 6x3.
