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Oksi-84 [34.3K]
3 years ago
11

QUICK ANSWER PLEASE

Mathematics
1 answer:
pochemuha3 years ago
5 0
The answer is 20cm :)
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Will someone please help me understand this?
mario62 [17]

Option A:

The length of diagonal JL is 3 \sqrt{5} \text { units }.

Solution:

In the quadrilateral, the coordinates of J is (1, 6) and L is (7, 3).

So that, x_1=1, y_1=6, x_2=7, y_2=3

To find the length of the diagonal JL.

Using distance formula:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

d=\sqrt{(3-6)^2+(7-1)^2}

d=\sqrt{(-3)^2+(6)^2}

d=\sqrt{9+36}

d=\sqrt{45}

d=\sqrt{3^2\times 5}

d=3\sqrt{ 5} units

The length of diagonal JL is 3 \sqrt{5} \text { units }.

Option A is the correct answer.

7 0
3 years ago
Read 2 more answers
A rectangle is drawn so that the width is 2 feet shorter than the length. The area of the rectangle is 3 feet square
Anastasy [175]

Answer:

length =3 feet

width = 1feet

Step-by-step explanation:

let the length be x

the width = x-2

area = length * width

3 = x*(x-2)

3 = x^{2} - 2x

x^{2} -2x-3 =0x^{2} +x -3x -3 =0

x(x+1)-3(x+1) =0

(x-3)(x+1)=0

x -3=0

x=3

thus,

the length =x =3 feet

the width =x-2 =3-2 = 1feet

8 0
3 years ago
Use a transformation to solve the equation. –3d = –27 A. d = –30 B. d = –24 C. d = –9 D. d = 9
nadezda [96]
When you divide both sides by three you get d=9

5 0
4 years ago
Read 2 more answers
Solve for 3a:<br> a + 4 = 4a + 2<br> 3a
expeople1 [14]

Answer:

x = 2/3

2/3*3 = 2

Step-by-step explanation:

7 0
3 years ago
Give statements and reasons
PolarNik [594]

Answer:

A two column proof is presented as follows;

Statement {}                                     Reason

1. AB ║ DE, BD bisects AE        {}    Given

2. ∠BAE = ∠AED, ∠ABD = ∠BDA {} Alternate ∠s are equal

3.  \overline {AC} =  \overline {EC} ,  \overline {BC} =  \overline {CD} {} {}            By definition of bisection of line AE by BD

4. ΔABC ≅ ΔEDC  {}                         By SAA, rule of congruency

Step-by-step explanation:

Step 1. AB ║ DE, BD bisects AE        {}    Given

Step 2. ∠BAE , ∠AED, and ∠ABD, ∠BDA {} are pairs of alternate angles formed by the parallel lines, AB and DE and are therefore, equal

Step 3.  \overline {AC} =  \overline {EC} ,  \overline {BC} =  \overline {CD}  The bisection of line gives two lines of equal length. The bisection of AE by BD gives,  \overline {AC} and  \overline {EC} where \overline {AC} =  \overline {EC}

Similarly, the bisection of BD by AE gives, \overline {BC} and  \overline {CD}, where  \overline {BC} =  \overline {CD}

Step 4. ΔABC ≅ ΔEDC  {}  By the Side-Angle-Angle (SAA), rule of congruency, which states that two triangles having two angles and the corresponding non included sides of each triangle equal to the other, the two triangles are congruent.

6 0
3 years ago
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