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Simora [160]
2 years ago
8

Please help I will give brainlyest!!!

Mathematics
2 answers:
Neko [114]2 years ago
8 0

Answer

cylinder!!

Step-by-step explanation:

so the points "(1, 1), (1, 4), (3, 4) and (3, 1)" they are all positive so this makes this easier tbh so it looks like this once u put them on a grah

.        .

.        .

its a rectangle then it says to rotate on y = 1 which u look at the graph u just put this rectangle on its side like this

.               .

.               .

so then look at the answer options

A.) Cone

B.)Cylinder

C.)Sphere

D.)Pyramid

so it CANT be A bc 1 its a rectangle and if it was a cone it would have 3 points, not 4, bc it would be a triangle

<u>It can be B</u> bc on a graph it will be 2D and a Cylinder has 4 points on a graph(in 2D) which the problem is telling you to make something 2D into something 3D...and is a rectangle in 2D

It CANT be a C bc in 2D it would be a circle and straight up, a square isnt a circle, and the points on the problem is a square ant there would be so many points to put down if it was a circle

It CANT be a D bc once again this would be a triangle and that would have 3 points, or maybe 5(if your looking overhead of the Pyramid where u can see all 4 corners, like a <u>square</u> then the middle point) so a square has all equal sides, rectagle does not, it has 2 and 2 equal sides. 2 sides being small and paralell, and 2 long sides being parallel.

:) have a good day

btw answer is

<h2><em><u>cylinder!!</u></em></h2>
iragen [17]2 years ago
3 0

Answer:

cylinder

Step-by-step explanation:

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1 year ago
Find the center of a circle with the equation: x2 y2−32x−60y 1122=0 x 2 y 2 − 32 x − 60 y 1122 = 0
mixas84 [53]

The equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

The center of the circle exists at (16, 30).

<h3>What is the equation of a circle?</h3>

Let, the equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

We rewrite the equation and set them equal :

$(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0

$x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

To learn more about center of the circle refer to:

brainly.com/question/10633821

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7 0
1 year ago
Which statement best describes parallel lines?
Margaret [11]

Answer:

Step-by-step explanation:

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If you increase your bicycle speed by 5.6 miles per hour, the speed will be 17.9 miles per hour. What is your bicycle speed now?
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Find 2x2 − 2z4 + y2 − x2 + z4 if x = −4, y = 3, and z = 2.
maw [93]
If you put in the substitutions it would be 2*2-(2*2*4)+(3*2)-(-4*2)+(2*4).
Simplified further by multiplying it would be 2*2-8+6--8+8
the negative 8 could be simplified further since the negatives cancel out so you'll have 2*2-8+6+8+8.
Then using the order of operations you would multiply the 2's together first to get 4 so you have 4-8+6+8+8. 
After that it's simple addition giving you an answer of -26.
I'm not sure if you're looking for the final answer or just the equation with substitutions but there's both.

3 0
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