Answer:
x = -1 and y = 6
Step-by-step explanation:
using x = -b/2a
x = -4 / 2(2)
x = -1
y = 2(-1)² + 4(-1) + 8
y = 2 - 4 + 8
y = 10 - 4
y = 6
Answer:
h³- 8h² + 16h
Step-by-step explanation:
The problem tells us that the length and width of these boxes are both 4 inches less than the height of the box.
So if we name <u>h the height of the box</u>, the <u>width of the box would be h - 4 </u>and the <u>height of the box would be h - 4.</u>
Now, the volume of a rectangular prism is given by V = height x width x length
So, considering the values we have in this problem we get:
V= height x width x volume
V = h (h-4)(h-4)
V= h(h-4)²
V= h (h²-8h + 16)
V = h³- 8h² + 16h
Therefore, the polynomial representing the volume of this box in terms of the height is h³- 8h² + 16h
Answer: 3.3 times 10^5 is bigger
Step-by-step explanation: 10^5= 10*10*10*10*10=100,000.
so 100,000 multiplied by 3.3 = 330,000
or 3.1 multiplied by 100,000 = 310,000 so it's obvious that 330,000 is bigger.
The solution to the first expression - 7+3(9-4)^2÷5 is given as 22.
To get the answer correctly, one must follow rudimentary rules of operations which are coined into the acronym BODMAS.
<h3>What is BODMAS?</h3>
This is the order in which mathematical operations must be executed.
B = Bracket
O = Orders (that is Powers, Indices or roots)
D= Division
M = Multiplication
A = Addition
S = Subtraction
Now lets see how we got 22 from the first set of operations:
<h3>Operation 1 (Example)</h3>
7+3(9-4)^2÷5 =
7+3 (5)^2÷5=
7+3 * 25÷5 =
7+3*5=
7+15=
22
Following the BODMAS rule and the example in Operation 1 above, we can state the remaining answers as follows:
<h3>
Operation 2</h3>
12/3-4+7^2 = 49
<h3 /><h3>
Operation 3</h3>
(7-3)×3^3÷9 = 12
<h3>Operation 4</h3>
5(7-3)^2÷(6-4)^3-9 = 1
<h3>Operation 5</h3>
3×(7-5)^3÷(8÷4)^2-5 = 1
<h3>Operation 6</h3>
9+(3×10)/5×2-12 = 9
See the link below for more about Mathematical Operations:
brainly.com/question/14133018
We have been given that Tim spends about 1/3 of each weekday sleeping and about 7/24 of each weekday in school. And we need to find what fraction of the weekday does Tim spend either sleeping or in school.
This means that we need to find the time he spends in sleeping when he is in the school.
Therefore, we have to add the time he spends in sleeping and the time he spends in school.
Therefore, required fraction is given by
Now in order to add the fractions, we have to make the denominator same.
Multiply the numerator and denominator of first fraction by 8 to make the same denominator.
Now, we have the same denominator hence, we can add the numerator
Therefore, Tim spends 15/24 hours each weekday sleeping in the school.
