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Elena-2011 [213]
2 years ago
10

For the function f(x)=1/x-2 +5 notice that a=1, h=2, k=5

Mathematics
1 answer:
saul85 [17]2 years ago
7 0

Answer:

x = 2 is the vertical asymptote

y = 5 is the horizontal asymptote

Step-by-step explanation:

The vertical asymptote is when it is undefined, or when the denominator is 0. This is when x = 2.

To find the horizontal asymptote, we need to find the value y can never be. Notice 1/(x-2) is never 0, so when y = 5, that value has to be 0, but this is not possible, so y = 5 is the vertical asymptote.

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Let the shorter diagonal be x, then
x^2 = 6^2 + 10^2 - 2 x 6 x 10 x cos 70 = 36 + 100 - 120 cos 70 = 136 - 41.04 = 94.96
x = sqrt(94.96) = 9.7 cm

The other angle of the parallelogram is 1/2(360 - 2(70)) = 1/2(360 - 140) = 1/2(220) = 110
Let the longer diagonal be y, then
y^2 = 6^2 + 10^2 - 2 x 6 x 10 x cos 110 = 36 + 100 - 120 cos 110 = 136 + 41.04 = 177.04
y = sqrt(177.04) = 13.3 cm.

Therefore, the length of the diagonals are 9.7 cm and 13.3 cm.
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