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katen-ka-za [31]
3 years ago
9

If z1 = 12(cos55° + isin55°) and z2 = 4(cos95° + isin95°), then |z1z2|= ???

Mathematics
1 answer:
zaharov [31]3 years ago
6 0
\bf \begin{cases}
z_1=12[cos(55^o)+i~sin(55^o)]\\\\
z_2=4[cos(95^o)+i~sin(95^o)]
\end{cases}\\\\
-------------------------------

\bf ~~~~~~\textit{ product of two complex numbers}\\\\
{{ r_1}}[cos({{ \alpha}})+isin({{ \alpha}})]\quad \cdot \quad {{ r_2}}[cos({{ \beta}})+isin({{ \beta}})]
\\\\\\
\implies {{ r_1\cdot r_2}}[cos({{ \alpha}} + {{ \beta}})+isin({{ \alpha}} + {{ \beta}})]\\\\
-------------------------------\\\\
z_1\cdot z_2\implies 12\cdot 4[cos(55^o+95^o)+i~sin(55^o+95^o)]
\\\\\\
48[cos(150^o)+i~sin(150^o)]
\\\\\\
|~48[cos(150^o)+i~sin(150^o)]~|\implies 48[cos(150^o)+i~sin(150^o)]
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