Answer:
(x-2) (x^2 -5)
Step-by-step explanation:
x^3 − 2x^2 − 5x + 10
We will factor by grouping
Take and x^2 out of the first two terms and -5 out of the last two terms
x^2 (x-2) -5(x-2)
Now we can factor out (x-2)
(x-2) (x^2 -5)
Answer:
Explanation Below
Step-by-step explanation:
1. -4 + | x - 1 | = 3
= -4 + | x - 1 | + 4 = 3 + 4
= | x - 1 | = 7
= x - 1 = -7 or x - 1 = 7
= x = -6 or x = 8
2. 6 + 4 | 2x + 6| = 14
= 6 + 4 | 2x + 6 | - 6 = 14 - 6
= 4 | 2x + 6 | = 8
= 4 | 2x + 6 | / 4 = 8/4
= 2x + 6 = -2 or 2x + 6 = 2
= x = -4 or x = -2
3. -10 + | -6 - x | = 1
= -10 + | -6 + x | + 10 = 1 + 10
= | -6 - x | = 11
= -6 - x = -11 or -6 - x = 11
= x = -17 or x = 5
4. | 7 - 2x | + 4 = 5
= | 7 - 2x | + 4 - 4 = 5 - 4
= | 7 - 2x | = 1
= 7 - 2x = -1 or 7 - 2x = 1
= x = 3 or x = 4
Here are the Steps:
SOLVING EQUATIONS CONTAINING ABSOLUTE VALUE(S)
Step 1: Isolate the absolute value expression.
Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.
Step 3: Solve for the unknown in both equations.
Step 4: Check your answer analytically or graphically.
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Answer:
x=-1,-2
Step-by-step explanation:
Multiply the given equation with (x+1) on both sides. We'll get,
x+2/x=-3
or,x^2+2=-3x
or,x^2+3x+2=0
or,x^2+2x+x+2=0
or,x(x+2)+1(x+2)=0
or,(x+2)(x+1)=0
or,x=-2,-1
Are there any repeating digits? There isn’t. Remember, on a device make sure you put 3 dots next to a decimal to show it’s repeating.
