Answer:
mutation, recombination, and immigration of genes.
Answer:
The correct answer is - 75% or 3/4.
Explanation:
In the given question, there is a cross between III-6 and III-7 that produced two double eyes monsters and expected one more. As given in the image that the A or single eye is dominant over the a or double eye then both parents must be heterozygous as they produced double eye offspring (aa) and they do have only one eye.
then chances of single eye offspring would be -
cross: Aa and Aa
gametes: A, a and A, a
Punnett square:
A a
A AA Aa
a Aa aa
so there are 75% chances to have a single eye and 25% chances for a double eye.
Answer:
c = Enzymatic activity
e = Attachment to ECM and cytoskeleton
f = Signal reception and relay
g = Transport
h = Intercellular junctions
i = Cell-cell recognition
a = Phospholipid bilayer
b = Fibers of extracellular matrix (ECM)
d = Microfilaments of cytoskeletons
Explanation:
c) Enzymatic activity is an indication of the amount of active enzymes present to increase a reaction rate
e) Attachment to ECM and cytoskeleton is enabled by integrins that take signals from the ECM and control signaling pathways of the cell
f) Signal reception and relay is the transduction of signal
g) Transport is the movement of matter in and out of the cell through the cell membrane
h) Intercellular junctions are the contact regions between adjacent cells and plasma membrane
i) Cell-cell recognition is power of the cell to decipher the different neighboring cells in the cell's environment
a) Phospholipid bilayer consists of a hydrophobic interior and a hydrophilic exterior
b) Fibers of extracellular matrix (ECM) are ECM associated the cell
d) Microfilaments of cytoskeletons consist of actin and aid in cellular movement.
Either A or C, however I lean towards C more.
D is obviously not the correct answer as Social Media is typically fairly biased while B is able to be edited by the public.
Hope this helps!
A nucleus is something that idek what ur talking abt
