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Kaylis [27]
3 years ago
8

There are 8 big fish for every___ small fish.

Mathematics
1 answer:
taurus [48]3 years ago
4 0
There are 8 big fish for every 10 small fish, ..... 5 small fish.
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What is the solution to this equation?<br><br> -2(2 - 4m) = 6(m + 3)
serg [7]

Answer:

m = 11

Step-by-step explanation:

-2(2 - 4m) = 6(m + 3)

Divide both sides by -2.

2 - 4m = -3(m + 3)

Distribute -3 on the left side.

2 - 4m = -3m - 9

Add 3m to both sides.

2 - m = -9

Subtract 2 from both sides.

-m = -11

Divide both sides by -1.

m = 11

6 0
3 years ago
Select the correct answer from each drop-down menu. The value of V42 is number. Its value is between
zalisa [80]

Answer:

Blank 1 would be irrational

Blank 2 would be 5 and 7

Step-by-step explanation:

hope this is correct

5 0
2 years ago
Chen completed the division problem below.
alekssr [168]

<u>Answer:</u>

B. He multiplied the dividend by 100 instead of 10.

<u>Step-by-step explanation:</u>

Chen had to divide 1.926 by 0.9. To make it easier to divide, he thought of multiplying both the dividend and the divisor by 10.

Chen multiplied the divisor by 10 but mistakenly multiplied the dividend by 100 instead of 10.

So his whole division problem was changed.

Therefore, the correct answer option is B. He multiplied the dividend by 100 instead of 10.

6 0
3 years ago
Read 2 more answers
You invested money in two funds. Last year, the first fund paid a dividend of 8% and the second a dividend of 5%, and you receiv
Angelina_Jolie [31]

You invested 11000 in in 2st fund and 9000 in 2nd fund

<h3><u>Solution:</u></h3>

Given that, You invested money in two funds.  

Last year, the first fund paid a dividend of 8% and the second a dividend of 5%, and you received a total of $1330.  

This year, the first fund paid a 12% dividend and the second only 2%, and you received a total of $1500.

Let the amount in Fund I be $x and amount in Fund II be $ y

Then, for last year ⇒ 0.08x+0.05y=1330 ----- eqn (1)  

And for this year ⇒ 0.12x+0.02y=1500 ------- eqn (2)  

Multiply (1) by 2 ⇒ 0.16 x + 0.1 y = 2660  

Multiply (2) by 5 ⇒ 0.6 x + 0.1 y = 7500

Subtract the two equations  

(2) ⇒ 0.6x + 0.1y = 7500

(1) ⇒ 0.16x + 0.1y = 2660

(-) --------------------------------

0.44x + 0 = 4840

x = 11000

Now, from eqn (2)  

0.12(11000) + 0.02y = 1500  

0.02y = 1500 – 1320  

0.02y = 180  

y = 9000

Hence, he invested 11000 in in 2st fund and 9000 in 2nd fund

5 0
3 years ago
Pls help I need a good grade I’ll brainlest
expeople1 [14]

Answer:

Step-by-step explanation:

A.

C.

3 0
3 years ago
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