Answer:
1.
The radius is given, so the radius is = 10
The radius is doubled to be a diameter, so (10 + 10) = 20 is your diameter
And to solve for circumference, your formula is;
C = 2πr
Where 'r' represents the radius, and 'π'(pi) is 22/7 or 3.14.
Plug in your values:-
C = 2πr
C = 2(3.14) x 10
C = 6.28 x 10
C = 62.8, so your circumference is 62.8.
2.
Your radius is half of your diameter, so,
D/2 = R
D = diameter
R = Radius
49/2 = 24.5 is your radius.
Your diameter is given, so the diameter is 49.
Use the formula we applied for circumference in our other problem;
C = 2πr
C = 2(3.14) x 24.5
C = 6.28 x 24.5
C = 153.86, so 153.86 is your circumference.
<span>First of all, F is true because (16 - 16)/(16 - 4) = 0. It just means when you plug in that number (16) you'll get 0. This will NOT happen for 4 because the 0 is in the denominator.
Look what happens if you have x = 4. This gives you 12/0, which is undefined. For some graphs, this is a hole, but let's look closer.
What happens if you have x = 3.9? You'll have 12.1/0.1. 3.9999? 12.0001/0.0001. The closer you get to 4, the closer you'll get to y = infinity.
But what if you have 4.1? 11.9/-0.1. You'll get the same results, but NEGATIVE infinity. So it is NOT a hole in the graph.
If you draw it out, you'll see that there is a vertical asymptote at x = 4.
B and F are true.
As for horizontal asymptotes, look at it like this: y = 16-16/16 - 4 means y = 0. There is no asymptote here. Try subbing in 1 = (x -16)/(x - 4).
Multiply by x - 4 on both sides
x - 4 = x - 16
There is no solution here; there will be an asymptote, so D is also true.
B, D, and F are true. ,"yahoo answers"//////////////////if i get busted at least i put down my main source (you know what I'm saying)</span>
Divide 159 by 39 to get around $4.08
0.55 as a fraction is 11/20
Answer: 0.2
Step-by-step explanation:
Given: The commuting time on a particular train is uniformly distributed over the interval (42,52).
∴ The probability density function of X will be :-
Thus, the required probability :-

Hence, the probability that the commuting time will be less than 44 minutes= 0.2