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3 years ago

Mr. McKay bought b boxes of crackers for $3 each and p pounds of cheese for $4 per pound. How much did he spend in all?

Mathematics

2 answers:

givi [52]3 years ago

6 0

<h2>Answer:</h2>

The total amount he spend is:

$ (3b+4p)

<h2>Step-by-step explanation:</h2>

It is given that:

Cost of 1 box of crackers= $ 3

This means that the cost of b boxes of crackers= $ 3b

Also,

Cost of 1 pound of cheese= $ 4

This means that the cost of p pounds of cheese= $ 4p

Hence, the total amount he spend=

Cost of b boxes of crackers+Cost of p pounds of cheese.

= $ 3b+$ 4p

= $ (3b+4p)

makvit [3.9K]3 years ago

3 0

You can't solve it without another piece of information, so the most you can do is write an equation (3b+ 4p), and once you know how many boxes he bought and the total (to figutre out how many pounds) or how many pounds and the total (to figure out how many boxes) or just the number of boxes and the number of pounds you can figure the problem out.

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Vesna [10]

Answer:

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Step-by-step explanation:

We use the Bayes Theorem to solve this question.

Bayes Theorem:

Two events, A and B.

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