If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.
Calculation for the Amount of IV
It is given that,
1L IV contains 60meq of kcal
⇒ 1000 mL of IV contains 60meq of kcal
⇒ 1 mL of IV will contain 60 / 1000 meq of kcal
As per the question,
The amount of IV infused in the patient = 400 mL
⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)
= 4 × 6
= 24 meq of kcal
Hence, the patient receives 24meq of kcal amount of IV.
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Answer:
144
Step-by-step explanation:
In the inverse we replace the place of x by y .
![g(x) = \sqrt[3]{x} - 3 \\ \\ x = \sqrt[3]{y} - 3 \\ \sqrt[3]{y} = x + 3 \\ y = {(x + 3)}^{3} \\ y = {(x + 3)}^{2} (x + 3) \\ y = ({x}^{2} + 6x + 9)(x + 3) \\ \\ y = {x}^{3} + 6 {x}^{2} + 9x + 3 {x}^{2} + 18x + 27 \\ \\ y = {x}^{3} + 9 {x}^{2} + 27x + 27 \\ \\ \\ g(x)^{ - 1} = {x}^{3} + 9 {x}^{2} + 27x + 27](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7Bx%7D%20%20-%203%20%5C%5C%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7By%7D%20%20-%203%20%5C%5C%20%20%5Csqrt%5B3%5D%7By%7D%20%20%3D%20x%20%2B%203%20%5C%5C%20y%20%3D%20%20%7B%28x%20%2B%203%29%7D%5E%7B3%7D%20%20%5C%5C%20y%20%3D%20%20%7B%28x%20%2B%203%29%7D%5E%7B2%7D%20%28x%20%2B%203%29%20%5C%5C%20y%20%3D%20%20%28%7Bx%7D%5E%7B2%7D%20%20%2B%206x%20%2B%209%29%28x%20%2B%203%29%20%5C%5C%20%5C%5C%20%20y%20%3D%20%20%7Bx%7D%5E%7B3%7D%20%20%2B%206%20%7Bx%7D%5E%7B2%7D%20%20%2B%209x%20%2B%203%20%7Bx%7D%5E%7B2%7D%20%20%2B%2018x%20%2B%2027%20%5C%5C%20%20%5C%5C%20y%20%3D%20%20%7Bx%7D%5E%7B3%7D%20%20%2B%209%20%7Bx%7D%5E%7B2%7D%20%20%2B%2027x%20%2B%2027%20%5C%5C%20%20%20%5C%5C%20%5C%5C%20g%28x%29%5E%7B%20-%201%7D%20%20%3D%20%20%7Bx%7D%5E%7B3%7D%20%20%2B%209%20%7Bx%7D%5E%7B2%7D%20%20%2B%2027x%20%2B%2027%20)
I hope I helped you^_^
