Answer:
60 miles
Step-by-step explanation:
Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian. If Brian starts 30 miles east of Ashok and both begin walking at the same time, how many miles will Brian walk before Ashok catches up with him?
Statement 1. Brian’s walking speed is twice the difference between Ashok’s walking speed and his own
Statement 2. If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds
Solution
A. Brian’s walking speed is twice the difference between Ashok’s walking speed and his own.
Let Brian speed=b
Ashok speed=a
Brian's walking speed=2(a-b)
b=2(a-b)
Divide both sides by 2
b/2=a-b
Ashok catches up in (time)= distance /( relative rate
=30/(a-b)
=30/(b/2)
=30÷b/2
=30*2/b
=60/b.
By that time Brian will cover a distance of
distance=rate*time
=b*60/b
=2(a-b)*60/2(a-b)
=60 miles
(2) If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds.
5a=3(a+b)
5a=3a+3b
5a-3a=3b
2a=3b
Answer:
Step-by-step explanation:
For the sake of clarity, assuming you meant:
1) Absolute Value or Modulus functions has one property that assures us that:
2) Solving for x
Not defined in Real Set of Numbers
Evaluating 
:
3) So, since for the first case the Discriminant Δ <0, then the solutions presented for 
. The only solution in the Real Set for the inequality is 
, i.e. x=-1.
Answer:
16
Step-by-step explanation:
Multiply it by 1/3 and it equals 16
Answer:
B. 4:3
Step-by-step explanation:
Note: I use the '&' mark to symbolize mixed fractions, since it's easy to mistake the whole number for part of the numerator. Don't do this for assignments, as it's not proper.
1 & 1/3 = 4/3
Thus, the answer is B. 4:3.
Answer:
both students are technically correct
Step-by-step explanation:
when the figure is reflected its other half mirrors it which means that all sides and angles are the same.
