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Anna11 [10]
4 years ago
12

Suppose that an investment of $13,000 grows in value at a rate of 9% per year. What is the growth factor for this investment?

Mathematics
2 answers:
Evgesh-ka [11]4 years ago
8 0
Growth rate is 9%,
so your growth factor will be (100+9)% = 109% = 109/100 = 1.09
pav-90 [236]4 years ago
5 0

Answer: c.  1.09

Step-by-step explanation:

The exponential growth equation is given by :-

f(x)=A(1+r)^x, where A is the initial amount , r is the rate of growth and x is the time period.

Here growth factor = 1+r

Given: The Initial value = $13,000

Rate of growth = 9%=0.09

Then, the exponential growth equation for the given investment will be

f(x)=13,000(1+0.09)^x\\\\\Rightarrow\ f(x)=13,000(1.09)^x

Here , the growth factor = 1.09

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Step-by-step explanation:

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Help on this one as well ii manged to get an answer but If you understand it or im wrong an you please explain ! thank you !!
AnnZ [28]
Almost got it!

x + 3 = 3(y + 2)/2 [Multiplied both sides by 3]
so x + 3 = (3y + 6)/2
2(x + 3) = 3y + 6 [Multiplied both sides by 2]
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3 years ago
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