Given the function f(x)=x^2+5x+5 , to get the zeros we solve using quadratic formula;
x=[-b(+or-) sqrt(b^2-4ac)]/(2a)
from our function;
a=1,b=5, c=5
thus,
x=[-5(+or-)sqrt(5^2-4*1*5)]/(2*1)
x=[-5(+or-)sqrt(25-20)]/2
x=[-5+/-sqrt(5)/2
The answer is option C
Answer:
<h3>6 feet</h3>
Step-by-step explanation
Using the pythagoras theorem;
Given
The length of the flag pole = 8 feet = opposite side
Length of the rope = 10 feet = hypotenuse
To determine how far out on the ground he need to secure the rope from the flagpole so that the rope is tight, we need to look for the adjacent. Using the equation
hyp² = opp² + adj²
10² = 8² + adj²
adj² = 100-64
adj² = 36
adj = √36
adj = 6feet
Hence the rope should be placed 6feet out of the ground
The answer to the question is 21
B, because the constant is on the bottom and the values are correct.
