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mariarad [96]
3 years ago
14

Use function notation to describe the transformation .

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
7 0
You would have to add a decimal point after 23 so it would look like this: 23.00, then line up the decimals of 23.00 and 59.8 and multiply them both and you should get : 1375.4

Hope this helps love!! <3

Message me for more help.
CaHeK987 [17]3 years ago
3 0
F(x)= -(x)+2 because the graph is reflected over the x-axis and it has a vertical shift up 2
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Find the value of (27/8)-2/3
Anvisha [2.4K]

The value of (27/8)-2/3 is..

Exact Form: 65/24

Decimal Form: 2.7083...…

Mixed Number Form: 2 17/24

8 0
3 years ago
Read 2 more answers
Given the values of x and y find the exact (fraction) values of all six trig ratios
Anna35 [415]

Answer:

Step-by-step explanation:

Distance of (-3,4) to origin = √((-3)^2+4^2) = 5

sinθ = 4/5

cosθ = -3/5

tanθ = 4/(-3) = -4/3

cscθ = 1/sinθ = 5/4

secθ = 1/cosθ = -5/3

cotθ = 1/tanθ = -3/4

4 0
3 years ago
Why mathematics is neccessary for students?explain​
tamaranim1 [39]

Answer:

Because depends on what you are going to work as you are most likely gonna use it

Step-by-step explanation:

3 0
3 years ago
SPIDER ~ HNYCMB<br> Find NY, YC, CM, AND MB.
zzz [600]

Answer:

HN = 66, NY = 27, YC = 30, CM = 27, MB = 42,

Step-by-step explanation:

When comparing the two shapes, SPIDER is 0.75 times larger than HNYCMB. Besides this small detail they are the same shape. We can determine this by identifying which sides are most similar and dividing them, if SP "=" HN, then to find the rate at which figure HNYCMB shrank is to divide SP by HN. 66/88 is 0.75. By multipying the sides of figure SPIDER by 0.75, we get our answers.

HN ~ SP, 66 = 88 * 0.75, HN = 66

NY ~ SR, 27 = 36 * 0.75, NY = 27

YC ~ RE, 30 = 40 *  0.75, YC = 30

CM ~ ED, 27 = 36 * 0.75, CM = 27

MB ~ DI, 42 = 56 * 0.75, MB = 42

BH ~ PI, BH = ? Try this one by yourself for understanding

ALSO PLEASE CHECK MATH BEFORE TURNING IN YOUR ASSIGNMENT MATH IS NOT MY STRONG SUIT

5 0
3 years ago
show that thw roots of the equation (x-a)(x_b)=k^2 are always real if a,b and k are real. Please I really need help with this
VLD [36.1K]

Answer:

see explanation

Step-by-step explanation:

Check the value of the discriminant

Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real

• If b² - 4ac = 0 roots are real and equal

• If b² - 4ac < 0 then roots are not real

given (x - a)(x - b) = k² ( expand factors )

x² - bx - ax - k² = 0 ( in standard form )

x² + x(- a - b) - k² = 0

with a = 1, b = (- a - b), c = -k²

b² - 4ac = (- a - b)² + 4k²

For a, b, k ∈ R then (- a - b)² ≥ 0 and 4k² ≥ 0

Hence roots of the equation are always real for a, b, k ∈ R


           

8 0
3 years ago
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