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aalyn [17]
3 years ago
9

HELP ASAP PLEASE. lines are graphed below. What can we conclude about them? Select all that apply.

Mathematics
2 answers:
Norma-Jean [14]3 years ago
8 0

The lines given are parallel. Parallel lines have equal slopes. Choices B and C work, while opposite reciprocal slopes are for perpendicular slopes. Choices A and D do not work.

insens350 [35]3 years ago
4 0
It’s obvious, the last three apply 2, 3, and 4
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In the derivation of the formula for the volume of a cone, the volume of the cone is calculated to be times the volume of the py
scZoUnD [109]

Answer:

B :it is the ratio of the area of the circle to the area of the square from a cross section.

Step-by-step explanation:

had this question on ed2020 and got it right^

5 0
3 years ago
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Write the algebraic expression that matches each graph? PLS HELP I NEED HELP!!!
Vladimir [108]

Looks like y = |x| because the slopes of the lines are both 1

You shift it to the right making it |x-2| and you shift it down making y = -2

combine to get <em>y = |x - 2| - 2</em>.

8 0
3 years ago
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In a certain clinical study, 15% of participants were classified as heavy smokers, 25% as light-smokers, and the rest as non-smo
Natasha_Volkova [10]

Answer:

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

Step-by-step explanation:

We have the following probabilities:

A 15% probability that a participant is classified as a heavy smoker.

A 25% probability that a participant is classified as a light smoker.

A 100% - 25% - 15% = 60% probability that a participant is classified as a non smoker.

A x% probability that a non smoker dies.

A 3x% probability that a light smoker dies.

A 5x% probability that a heavy smoker dies.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

This problem is:

What is the probability of the participant being a non-smoker, given that he died?

P(B) is the probability that the participant is a non smoker. So

P(B) = 0.6

P(A/B) is the probability that the participant dies, given that he is a non smoker. So:

P(A/B) = x

P(A) is the probability that the participant dies:

P(A) = P_{1} + P_{2} + P_{3}

P_{1} is the probability that a heavy smoker is selected and that he dies. So:

P_{1} = 0.15*5x = 0.75x

P_{2} is the probability that a light smoker is selected and that he dies. So:

P_{2} = 0.25*3x = 0.75x

P_{3} is the probability that a non-smoker is selected and that he dies. So:

P_{3} = 0.60*x = 0.60x

The probability that a participant dies is:

P(A) = P_{1} + P_{2} + P_{3} = 0.75x + 0.75x + 0.60x = 2.10x

The probability of the participant being a non-smoker, given that he died, is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.6x}{2.10x} = \frac{0.6}{2.10} = 0.2857

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

7 0
3 years ago
Please help me answer these.
Andrews [41]

Answer:

1 is 3.5

2 is 480

3 is 15

4 is 2.5

5 is B and D

7 0
2 years ago
Logarithms:
bogdanovich [222]

Answer:

  • 2^45 or ≈ 3.5*10^13

Step-by-step explanation:

<u>Given equation</u>

  • f(t) = 2^(kt)
  • f - number of cells, t - number of months, k- coefficient

<u>We got 32 cells in the first month. It means:</u>

  • t = 1, f(1) = 32

<u>Using these numbers we can find the coefficient k:</u>

  • 32 = 2^(k*1)
  • 2^5 = 2^k
  • k = 5

<u>Then the equation becomes:</u>

  • f(t) = 2^(5t)

<u>Average time is 9 months, we can calculate the number of cells:</u>

  • f(9) = 2^(5*9) = 2^45 ≈ 3.5*10^13
5 0
3 years ago
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