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Marysya12 [62]
4 years ago
6

Manipulate formulas YALL PLZ HELP I BEG U i’ll give brainliest

Mathematics
1 answer:
disa [49]4 years ago
6 0

Answer:

\sqrt{\frac{3V}{\pi h} }

Step-by-step explanation:

We have V = \frac{1}{3} \pi r^2h.

We can multiply both sides by 3 to get:

3V =  \pi r^2h

Divide by \pi by both sides

\frac{3V}{\pi} =  r^2h

And divide by h by both sides:

\frac{3V}{\pi h}  =  r^2

And finally take the square root of both sides.

\sqrt{\frac{3V}{\pi h} }  =  r

Done!

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A 2-pint bottle of dish soap costs $9.44. What is the price per cup?
LiRa [457]
$2.36 per cup. there are two cups in a pint, so if there are 2 pints then there are 4 cups. 9.44/ 4 is 2.36
7 0
3 years ago
Only find the vertex and axis of symmetry
lara [203]

Answer:

vertex (5,2)

axis of symmetry: x=5

Step-by-step explanation:

vertex (h,k)

y = a(x - h)² + k

f(x)=(x-5)²+2        a = 1     h = 5      k = 2

vertex (5 , 2)

The axis of symmetry always passes through the vertex of the parabola. The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola.

x = 5

5 0
3 years ago
Suppose that Y takes on the values {0, 1, 2, 3}, each with probability 1/4. Take a random sample of 5 numbers from this distribu
arsen [322]

Answer:

The total number of samples that give this outcome is 5.

Step-by-step explanation:

Since Y takes values in {0,1,2,3}, For us to have that Y_1+Y_2+Y_3+Y_4+Y_5=1 implies that all of them are zero but one. The one that is non-zero necessarily is equal to 1. To calculate the number of samples that give this outcome is equivalent to counting the total number of ways in which we can pick the i-index such that Y_i=1. Note that in this case we can either choose Y1 to be 1, Y2 to be 1 and so on. So, the total number of samples that give this outcome is 5.

8 0
3 years ago
A shirt regularly priced at $36.00 was on sale for 25% off.
VLD [36.1K]

Answer:

C

Step-by-step explanation:

find out the 35% OF 36.00

36x35%=9

36-9=27

3 0
3 years ago
The mass, m grams, of a radioactive substance, present at time t days after first being observed, is given by the formula m=24e^
Reika [66]

Answer:

(i) The value of<em> m</em> when t = 30 is 13.2

(ii) The value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) The rate of the mass when t=50 is -0.18            

Step-by-step explanation:

(i) The <em>m</em> value when t = 30 is:

m = 24e^{-0.02t} = 24e^{-0.02*30} = 13.2

Then, the value of<em> m</em> when t = 30 is 13.2

(ii) The value of the mass when t=0 is:

m_{0} = 24e^{-0.02t} = 24e^{-0.02*0} = 24    

Now, the value of <em>t </em>is:

ln(\frac{m_{0}/2}{24}) = -0.02t

t = -\frac{ln(\frac{24}{2*24})}{0.02} = 34.7

Hence, the value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) Finally, the rate at which the mass is decreasing when t=50 is:

\frac{dm}{dt} = \frac{d}{dt}(24e^{-0.02t}) = 24(e^{-0.02t})*(-0.02) = -0.48*                            (e^{-0.02*50}) = -0.18

Therefore, the rate of the mass when t=50 is -0.18.

I hope it helps you!                  

3 0
3 years ago
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