All categories

3 years ago

What is the value of x is?

Mathematics

1 answer:

marin [14]3 years ago

3 0

The applicable theorem is the one that tells you the exterior angle is equal to the sum of the opposite interior angles.
9x = (5x) +(9 +x)
9x = 6x +9 . . . . . . . . collect terms
3x = 9 . . . . . . . . . . . . subtract 6x
x = 3 . . . . . . . . . . . . . divide by 3

The value of x is 3.

_____
The angles (clockwise from left) are then
(9*3)° = 27°
(5*3)° = 15°
(9 +3)° = 12°
This is an obtuse triangle, obviously not drawn to scale.

You might be interested in

The product of 5 and a number x is 1/4. what is the value of x?

solniwko [45]

The mathematical expression is
5x = 1/4
Divide:
x = (1/4)/5 = (1/4)*5 = 5/4 (ANSWER)

4 0

3 years ago

Read 2 more answers

Please help me due today and giving 23 points

vladimir2022 [97]

Answer:

The answer is b. 4*3 2/5.

Step-by-step explanation:

It states 4 times the amount Ruby mixed. Ruby mixed it 3 2/5 solution. So you would right out 4 x 3 2/5.

5 0

2 years ago

Read 2 more answers

A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute q in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute h in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for d, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for d in the second equation to find h, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for d and 16 for h in the third equation to find q, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

6 0

3 years ago

Can someone help me with this please? Thank you!

Finger [1]

Answer:

528 cm²

Step-by-step explanation:

First I would calculate the area of the side rectangles:

20 x 9 = 180 cm²

There are two identical rectangles on both sides so i would x2

180 x 2 = 360 cm²

The area of the middle rectangle:

6 x 20 = 120 cm²

The area of the triangles:

Area of a triangle = (Base x Height)/2

8 x 6 = 48

48 ÷ 2 = 24

There are two identical triangles on the bottom and the top so x2

24 x 2 = 48

Now add all the values up:

360 + 120 + 48 = 528 cm²

I hope this helps!

5 0

2 years ago

What is 3/5 ÷ 3/7 help please

Rus_ich [418]

3/5 / 3/7

= 3/5 * 7/3

= 7/5 or 1 2/7

8 0

3 years ago