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3 years ago

What’s the Answer of this question plz? The total

Mathematics

1 answer:

ryzh [129]3 years ago

4 0

Answer:

I think it's six

Step-by-step explanation:

A= 1

b= 2

c= 3

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10. Joseph and Tabitha were hiking and had a choice between two trails. One was

Nataly [62]

Answer:

10+5=15 sow longer trail is 15

3 0

3 years ago

A new car is purchased for 17000 dollars. The value of the car depreciates at 12.25% per year. What will the value of the car be

Scilla [17]

Answer:

$P(t=14) = 17000 (1-0.1225)^{14}= 2728.404$

Step-by-step explanation:

for this case we have the following model for the cost of the car:

$P(t) = P_o (1-r)^t$

Where $P_o$ is the initial amount on this case 17000, t the amount of years after the initial year and r the depreciation rate on this case:

$r= \frac{12.25}{100}=0.1225$

And for t =14 we can replace into the equation and we got:

$P(t=14) = 17000 (1-0.1225)^{14}= 2728.404$

5 0

3 years ago

Jimmy's 9th-grade class is made up of 223 students. He wants to know the average height for the students in his class, and he wa

kari74 [83]

I believe that the smallest number of students Jimmy can measure is 223, and I know this is right because one of my teachers had us do this probem and she said this was it.

5 0

3 years ago

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Suppose a certain capsule is manufactured so that the dosage of the active ingredient follows the distribution Y ~ N(μ = 10 mg,

lianna [129]

Answer:

(a) Probability that Y falls into the dangerous region is 0.0013.

(b) Probability that the mean Y-bar falls into the dangerous region is 0.00001.

Step-by-step explanation:

We are given that a certain capsule is manufactured so that the dosage of the active ingredient follows the distribution Y ~ N(μ = 10 mg, σ = 1 mg).

A dosage of 13 mg is considered dangerous.

Let Y = dosage of the active ingredient

The z-score probability distribution for normal distribution is given by;

Z = $\frac{ Y-\mu}{\sigma} } }$ ~ N(0,1)

where, $\mu$ = population mean = 10 mg

$\sigma$ = standard deviation = 1 mg

(a) Probability that Y falls into the dangerous region is given by = P(Y $\geq$ 13 mg)

P(Y $\geq$ 13 mg) = P( $\frac{ Y-\mu}{\sigma} } }$ $\geq$ $\frac{ 13-10}{1} } }$ ) = P(Z $\geq$ 3) = 1 - P(Z < 3)

= 1 - 0.9987 = 0.0013

The above probability is calculated by looking at the value of x = 3 in the z table which has an area of 0.9987.

(b) We are given that a dosage of 13 mg is considered dangerous. And we sample 49 capsules at random.

Let $\bar Y$ = sample mean dosage

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar Y-\mu}{\frac{\sigma}{\sqrt{n} } } } }$ ~ N(0,1)

where, $\mu$ = population mean = 10 mg

$\sigma$ = standard deviation = 1 mg

n = sample of capsules = 49

So, Probability that the mean Y-bar falls into the dangerous region is given by = P( $\bar Y$ $\geq$ 13 mg)

P(Y $\geq$ 13 mg) = P( $\frac{\bar Y-\mu}{\frac{\sigma}{\sqrt{n} } } } }$ $\geq$ $\frac{13-10}{\frac{1}{\sqrt{49} } } } }$ ) = P(Z $\geq$ 21) = 1 - P(Z < 21)

= 0.00001

6 0

3 years ago

What is the meaning of IQR

vfiekz [6]

It’s the parts on the graph so it would be Q1 Q2 Q3

6 0

3 years ago

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