12 goes with 6 and 5 with 10
(6x^4+12x^2)+(-5x^2-10)
(6x^2)(x^2+2)+(-5)(x^2+2)
undistribute
(x^2+2)(6x^2-5)
The formula is y2 - y1/x2 - x1. The answer would be 3/4 once simplified.
<span>2[4x-5(2x-1)]
=</span><span>2[4x- 10x + 5]
= 2(-6x + 5)
= -12x + 10</span>
You will use this information to create the numerical (standard form) value of each.
4 thousands, 12 hundreds (1 thousand and 2 hundred) = 5200
4 thousands, 6 hundreds, 5 tens = 4650
5200 is greater than 4650.
V= 4/3 π R^3
17 x 17 x 17 = 4913 x 4 = 19652 / 3 = 6550.66667
or 6550.7
6550.7 x 3.14 = <span>20569.198
V = 20569.2</span>
