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weeeeeb [17]
3 years ago
7

1+39(12-44)=x find x

Mathematics
2 answers:
VashaNatasha [74]3 years ago
8 0
First distribute the 39 among the numbers in the parentheses

1 + 468 - 1,716 = x

then simplify the left side

-1,247 = x

hope this helps
Eduardwww [97]3 years ago
6 0

Answer:

The answer is x=−1247

Step-by-step explanation:

Let's solve your equation step-by-step.

1+39(12−44)=x

Step 1: Simplify both sides of the equation.

1+39(12−44)=x

1+−1248=x

(1+−1248)=x(Combine Like Terms)

−1247=x

−1247=x

Step 2: Flip the equation.

Answer: x=−1247

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A number y is no more than -8 what is the inequality
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An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
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divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
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where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
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I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
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4 0
3 years ago
How do you write -4 1/5 as an improper fraction
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-21/5

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