Two fold rotational symmetry
Answer:
Area of rhombus = 96 inch²
Step-by-step explanation:
Given:
Side length of rhombus = 10 inch
Length of longer diagonal = 16 inch
Find:
Area of rhombus
Computation:
We know that, diagonals of rhombus perpendicular bisect each other
So,
Half of small diagonal = √Side length of rhombus² - Half length of longer diagonal²
Half of small diagonal = √10² - 8²
Half of small diagonal = √100 - 64
Half of small diagonal = √36
Half of small diagonal = 6 inch
Length of smaller diagonal = 2 x 6
Length of smaller diagonal = 12 inch
Area of rhombus = (Product of diagonals)/2
Area of rhombus = (16 x 12)/2
Area of rhombus = 96 inch²
Answer:
64.2580645161 words in a minute
Step-by-step explanation:
Hope that helps!
<span>So we want to start at 476. Then subtract and add 107 to find the standard deviation increments above and below.
</span><span>476-107=369
</span>369-107=199
199-107=29
