The ultimatum game is a popular experiment. It is widely used in economic experiments. In this game two people are matched randomly, one player as a proposer and one as a responder. They are told they would play a game exactly once. The proposer is given an amount of money and he has the task to split or divide that amount between himself and the responder. When the proposer conveys the decision, the respondent then decides whether to accept or reject it. If the responder accepts, then both earn the amount split per the proposer's suggestion. If responder rejects then both the proposer and responder receive nothing.

For example a player is given a sum of money, $ 20. He is called proposer. He is told to offer some endowed amount (from $1 to $20) to the other player who is responder. If responder accepts this amount offer they both keep that money but if the responder rejects the offer then both players get nothing.

3 0

3 years ago

Please help me. And please show your work. Thanks

Crazy boy [7]

The answer is 387.71
Formula: pi * r (r + (square root of h^2 + r^2) )
Plug in and solve.

3 0

4 years ago

Use the box plots comparing the number of males and number of females attending the latest superhero movie each day for a month

Maksim231197 [3]

Answer:

Part A:

The interquartile range is approximately 10

Part B:

The difference between the median values for each data set is approximately 6

Part C:

i) More widely distributed and concentrated to the beginning of the month

The better measure of the center for the male dataset is the median

ii) The skewed distribution

The mean is the better measure of center for the dataset

Part D;

A possible reason for the outlier is by chance

Step-by-step explanation:

Part A:

The interquartile range, IQR, is the width of the box in the box plot = The difference between the third quartile, Q₃ and the first quartile, Q₁ = Q₃ - Q₁

From the diagram, Q₃ ≈ 13, Q₁ ≈ 3

∴ The interquartile range, IQR = 13 - 3 = 10

Part B:

From the diagram of the box plot, the median value, of the males, M-Q₂ ≈ 12

The median value for the females, F-Q₂ ≈ 18

The difference, M-Q₂ - F-Q₂ = 18 - 12 ≈ 6

The difference between the median values for each data set, d = M-Q₂ - F-Q₂ ≈ 6

Part C:

i) The distribution of the of the male dataset for the male has more data on the left of the box plot, with the median located approximately at the center and an outlier at end of the month

The better measure of the center for the male dataset is the median

ii) The distribution of the dataset for the females is skewed (concentrated on the right of the plot). The data set has no outlier and the first quartile is 0, while the third quartile corresponds with the maximum value at 21, the first quartile is 15 and the IQR is approximately 6

The better measure of center for the dataset is the mean, as the difference between the value of the first quartile, 0, and the other data points is more accounted for by the mean

Part D;

The possible reason for the outlier in the male dataset can be attributed to chance

4 0

3 years ago