Here, 2 1/4 r = 10
9/4 r = 10
r = 10*4 /9
r = 40 / 9
r = 4 4/9
In short, Your Answer would be Option C
Hope this helps!
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the
KM² = KE² + ME²KM² = 8² + (3√5)² = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM) = 1/2 * 3√5 * (40 + 24) = 1/2 * 3√5 * 64 = 3 x 2.23 * 32 = 214.66 units²
G(x) = 3x + 4
g(-4) = 3(-4) + 4
g(-4) = -12 + 4
g(-4) = -8
3 consecutive means
x, x+1, x+2
OR
x, x-1, x-2
the equation based on givens and first equation is:
2(x) + 2(x+1) = 69 - (x+2)
4x + 2 = 67 - x
5x = 65
x = 13
so the largest would be x+2 or 15
The correct answer in my opinion is 2x+3y= -6 <span />
