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Gemiola [76]
3 years ago
14

The function, f(x), is plotted below.

Mathematics
2 answers:
Talja [164]3 years ago
8 0

Answer:

1

2

DNE

Step-by-step explanation:

tester [92]3 years ago
4 0

Answer:1 2 DNE

Step-by-step explanation:

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Determine what type of observational study is described. Explain. Vitamin D is important for the metabolism of calcium and expos
ICE Princess25 [194]

Answer:

thats too long to read but good luck!

Step-by-step explanation:

3 0
3 years ago
Find the slope of the line passing through the points (-6,2), (0,-6).A 6B 2.C-4/3DOE-3/1
NNADVOKAT [17]

Given data:

The first point given iis (a, b)=(-6,2).

The second point given is (c,d)=(0, -6).

The expression for the slope is,

m=(d-b)/(c-a)

Substitute the given points in the above expression.

m=(-6-2)/(0-(-6))

=(-8)/(6)

=-4/3

Thus, the slope of the line is -4/3, so (C) option is correct.

8 0
1 year ago
HElPP<br> what is 232 if it's scaled down by a factor of 1/10
Lynna [10]

Answer:

23.2

Step-by-step explanation:

Scaling down by a factor of 1/10 is equal to dividing the number by 10.

So 232 getting scaled down by a factor of 1/10 is equivalent to 232/10 i.e. 23.2.

3 0
3 years ago
How do you write 35 over 20 As a percentage
lara31 [8.8K]
In order to write \frac{35}{20} as a percentage, we must first convert the fraction into a decimal. We can do that simply by dividing.

35 / 20 = 1.75

In order to convert a fraction to a decimal, we must multiply it by 100

1.75 * 100 = 175%

\frac{35}{20} as a percentage is 175%.
Hope that helped =)
4 0
3 years ago
Read 2 more answers
A lake has a large population of fish. On average, there are 2,400 fish in the lake, but this number can vary by as much as 155.
AleksAgata [21]

Answer:

Minimum population of fish in lake = 2400 - 155 = 2245

Maximum population of fish in lake = 2400 + 155 = 2555

Step-by-step explanation:

population of fish in lake = 2400

Variation of fish = 155

it means that while current population of fish is 2400, the number can increase or decrease by maximum upto 155.

For example

for increase

population of fish can 2400 + 2, 2400 + 70, 2400 + 130 etc

but it cannot be beyond 2400 + 155.

It cannot be 2400 + 156

similarly for decrease

population of fish can 2400 - 3, 2400 - 95, 2400 - 144 etc

but it cannot be less that 2400 - 155.

It cannot be 2400 - 156

Hence population can fish in lake can be between 2400 - 155 and 2400 + 155

minimum population of fish in lake = 2400 - 155 = 2245

maximum population of fish in lake = 2400 + 155 = 2555

4 0
3 years ago
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