Answer:
broad sense heritability = 0.75
Step-by-step explanation:
Step 1: Variables
phenotypic variation (Vp)
genotype variation (Vg)
environment variation (Ve)
broad sense heritability (H)
Step 2: Formulas:
H = Vg / Vp
Vp = Vg + Ve
Vg = Vp - Ve
Step 3: Given data
Vp = 20
Ve = 5
Step 4: Computation
Vg = 20 - 5 = 15
H = 15 / 20
H = 0.75
Hope this helps!
I believe the appropriate volume is 160.
\left[x \right] = \left[ -18\right][x]=[−18]equation of a line that is parallel
50(4)= 200
There are 200 pattern blocks.
Hope this helps!
