Question

Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = _____Ω 5.4 x 10-1 5.0 x 109 2.0 x 10-18 1.6 x 10-2

Answer 1

Answer:

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030 $cm^2$

and specific resistance (ρ) = $1.8 \times 10^{-6}$ ohm-cm.

Use the formula  R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, $R=\frac{1.8 \times 10^{-6} \times 270}{0.030}$ ohm

Simplify:

R = 0.0162 ohm = $1.62\times 10^{-2}$ ohm

Therefore, the resistance of copper wire is,  $1.62\times 10^{-2}$ Ω