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lapo4ka [179]
2 years ago
8

Solve the following system of equations using the SUBSTITUTION method. Show all your work! x = 2y + 1 x + y = 4

Mathematics
1 answer:
Alexxandr [17]2 years ago
3 0

Answer:

Step-by-step explanation:

4x+y=14

x-2y=8

then;

x=8-2y

substitute;

4(8-2y)+8-2y=14

32-8y+8-2y=14

40-10y=14

26=10y

y=2.6 , work out 4x+2.6=14 to get x

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Answer:

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Vikki [24]
The equation of the circle: (x-a)^2+(y-b)^2=r^2

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We have:

x^2-4x+y^2+8y=-4\\\\x^2-2x\cdot2+y^2+2y\cdot4=-4\ \ \ |add\ 2^2\ and\ 4^2\ to\ both\ sides\\\\\underbrace{x^2-2x\cdot2+2^2}_{(*)}+\underbrace{y^2+2y\cdot4+4^2}_{(*)}=-4+2^2+4^2\\\\(x-2)^2+(y+4)^2=-4+4+16\\\\(x+2)^2+(y-4)^2=16\\\\(x+2)^2+(y-4)^2=4^2

Answer:
The center: (-2; 4)
The radius: r = 4
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