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2 years ago

The average distance between the Earth and the Moon is 384 400 km. Express it in standard form.

Mathematics

1 answer:

ycow [4]2 years ago

3 0

Answer:

$3.84\times10^8\ m$

Step-by-step explanation:

It is given that,

The average distance between the Earth and the Moon is 384 400 km.

We need to express in in standard form.

1 km = 1000 m

It means,

384400 km = 384400000 km

= $3.84\times10^8\ m$

Hence, the average distance between the Earth and the Moon is $3.84\times10^8\ m$ .

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I need the corresponding letters on the equation. A= B= C= D= E= F= G=

REY [17]

Answer:

A = 3

B = 1

C = 2

D = 10

E = 2

F = Not listed

G = 1

Step-by-step explanation:

$\sqrt[3]{270x^5y^7} =\sqrt[3]{27*10x^5y^7}=3xy^2\sqrt[3]{10x^2y}$

8 0

2 years ago

A square field has an area of 479 ft what is the approximate length of a size of the field

MissTica

Answer:

21.9 ft

Step-by-step explanation:

The area of a square is the square of the side length, so the side length is the square root of the area:

... s = √(479 ft²) ≈ 21.886 ft

This is approximately 21.9 ft.

4 0

2 years ago

In a school, the ratio of musicians to athletes is 3 : 1. The number of musicians is how many times the number of athletes? ANS

loris [4]

Answer:

The number of musicians in the school is 3 times the number of athletes

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Write the linear inequality shown in the graph.

Korolek [52]

Fist, in the equation y=mx+b, b is the y-intercept. The y-intercept is the poin on the line that crosses the x-axis; the y-intercept is the value of yThese equations follow that format.
Y=mx+b
y $\geq$ 3x-4. <-----In this equation, the slope(m)=3 b= -4.

On the graph, we can see that the line crosses the x-axis at y=-4. Knowing that, we can eliminate the answer choices with +4 in the inequality.

The next step, is to pick an (x,y) coordinate that is in the shaded region and plug it into the remaining 2 inequalities. Which ever inequality is true after you solve it, that is the correct answer.
For example, I'll choose to plug in (-4,4) into the y $\geq$ 3x-4.
y $\geq$ 3x-4.
(4) $\geq$ (3(-4))-4.
(4) $\geq$ (-12)-4.
(4) $\geq$ -16

So, this statement is true becasue -16 is less than positive 4. Therefore, the correct answer would be y $\geq$ 3x-4. Hope that helped! Comment back with any further questions!

6 0

2 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

2 years ago