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3 years ago

The average distance between the Earth and the Moon is 384 400 km. Express it in standard form.

Mathematics

1 answer:

ycow [4]3 years ago

3 0

Answer:

$3.84\times10^8\ m$

Step-by-step explanation:

It is given that,

The average distance between the Earth and the Moon is 384 400 km.

We need to express in in standard form.

1 km = 1000 m

It means,

384400 km = 384400000 km

= $3.84\times10^8\ m$

Hence, the average distance between the Earth and the Moon is $3.84\times10^8\ m$ .

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Find the perimeter of the polygon. Round your answer to the nearest tenth.

lubasha [3.4K]

Answer:

Perimeter is 38.8 units and approximately 39 units

Step-by-step explanation:

Given: Graph

To find: perimeter of the polygon

Solution:

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

As per the graph,

point P is (-2,11)

point Q is (-4,6)

point R is (2,0)

point S is (1,7)

point T is (8,7)

$PQ=\sqrt{(-4+2)^2+(6-11)^2}=\sqrt{(-2)^2+(-5)^2}=\sqrt{29}=5.4\,\,units\\QR=\sqrt{(2+4)^2+(0-6)^2}=\sqrt{(6)^2+(-6)^2}=\sqrt{72}=8.5\,\,units\\RS=\sqrt{(1-2)^2+(7-0)^2}=\sqrt{(-1)^2+(7)^2}=\sqrt{50}=7.1\,\,units\\ST=\sqrt{(8-1)^2+(7-7)^2}=\sqrt{(7)^2+(0)^2}=\sqrt{49}=7\,\,units\\PT=\sqrt{(8+2)^2+(7-11)^2}=\sqrt{(10)^2+(-4)^2}=\sqrt{116}=10.8\,\,units$

Perimeter refers to sum of lengths of all the sides.

Perimeter = $5.4+8.5+7.1+7+10.8=38.8$

Or approximately 39 units

3 0

3 years ago

Z=5x- 11y can someone please help

Feliz [49]

Answer:

z+11y/5 = x

Step-by-step explanation:

Since you are solving for x, you want to isolate the variable. You do that by adding 11y to both sides, which cancels out the -11y. From that you should have z+11y = 5x. To cancel out the 5x you need to divide both sides by 5 to get z+11y/5 = x. Hope this helps :)

3 0

3 years ago

How many faces does the polyhedron have? _ faces How many vertices does the polyhedron have? _vertices How many edges does the p

Sindrei [870]

The polyhedron has:

6 Faces, 8 vertices and 12 edges in total.