Line SU intersects line TV at point R. What is the value of x in degrees?
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You can solve for C using the law of cosines.
P, Q, and R are the angles of the triangle and p, q, and r are the lengths of the sides of the triangle opposite of the angles. That means p = 10ft, q = 12ft, and r=5ft. The law of cosines states that:
Since we're looking for the measure of angle P, we would use the first equation,
. Plug the values we have for the sides of the triangle into the equation and solve for P:
The measure of angle P is about 55<span>°.</span>
P, Q, and R are the angles of the triangle and p, q, and r are the lengths of the sides of the triangle opposite of the angles. That means p = 10ft, q = 12ft, and r=5ft. The law of cosines states that:
Since we're looking for the measure of angle P, we would use the first equation,
The measure of angle P is about 55<span>°.</span>
