Answer:
i cant see the answers what do they say?
Step-by-step explanation:
<u>Answer-</u>
<u>Solution-</u>
We know that arc length is the product of radius and central angle in radian.
i.e
Here,
So,
6 units to the left of 0 on a number line
Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)