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Hoochie [10]
3 years ago
11

A skyrocket is launched from a 8-foot-high platform with an initial speed of 220 feet per second. The polynomial 16t^ ^ 2+220t+8

gives the height in feet that the skyrocket will rise in t seconds. How high will the rocket rise if it has a 7-second fuse?
The equation above is - 16t ^ 2 + 220t + 8

A) 748
B) 764
C) 788
D) 882
Mathematics
1 answer:
DedPeter [7]3 years ago
3 0

Given :

A skyrocket is launched from a 8-foot-high platform with an initial speed of 220 feet per second.

The polynomial -16t² + 220t + 8 gives the height in feet that the skyrocket will rise in t seconds.

To Find :

How high will the rocket rise if it has a 7-second fuse?

Solution :

Since, it is given that the rocket has a fuse time of 7 seconds.

Putting value of 7 sec in given equation, we get :

Height = -16×( 7 )² + 220×( 7 ) + 8

Height = 764 m

Therefore, height of rocket in 7 second fuse is 764 m.

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Answer: (-2, -1)

Step-by-step explanation: Since these lines are already graphed, we are looking for their point of intersection. This point where the two lines intersect will represent the <em>x</em> and <em>y</em> that is the solution to this system of equations.

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What is the end behavior of the graph of f(x) = x5 – 8x4 + 16x3?
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