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3 years ago

CAN SOMEBODY HELP PLEASE! I WOULD REALLY APPRECIATE IT

Mathematics

1 answer:

OlgaM077 [116]3 years ago

5 0

Answer:

A) 163,840

Step-by-step explanation:

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1/4x + x = -3+ 1/2x, what is x?

USPshnik [31]

Answer:

x = -4

Step-by-step explanation:

Solve for x:

(5 x)/4 = x/2 - 3

Put each term in x/2 - 3 over the common denominator 2: x/2 - 3 = x/2 - 6/2:

(5 x)/4 = x/2 - 6/2

x/2 - 6/2 = (x - 6)/2:

(5 x)/4 = (x - 6)/2

Multiply both sides by 4:

(4×5 x)/4 = (4 (x - 6))/2

(4×5 x)/4 = 4/4×5 x = 5 x:

5 x = (4 (x - 6))/2

4/2 = (2×2)/2 = 2:

5 x = 2 (x - 6)

Expand out terms of the right hand side:

5 x = 2 x - 12

Subtract 2 x from both sides:

5 x - 2 x = (2 x - 2 x) - 12

5 x - 2 x = 3 x:

3 x = (2 x - 2 x) - 12

2 x - 2 x = 0:

3 x = -12

Divide both sides of 3 x = -12 by 3:

(3 x)/3 = (-12)/3

3/3 = 1:

x = (-12)/3

The gcd of -12 and 3 is 3, so (-12)/3 = (3 (-4))/(3×1) = 3/3×-4 = -4:

Answer: x = -4

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4 years ago

A 20-row theater has three sections of seating. In each section,

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I'm not 100% sure but try A.

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3 years ago

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Find Mx, My, and (x, y) for the lamina of uniform density rho bounded by the graphs of the equations. y = x2/3, y = 0, x = 1

erik [133]

Answer:

$\mathbf{(\overline x , \overline y ) = (\dfrac{5}{8}, \dfrac{5}{14})}$

Step-by-step explanation:

Given that:

$y = x^{2/3}$ at y = 0 , x = 1

Then:

Area = $\int^{1}_{0} x^{2/3} \ dx$

Area = $\begin {bmatrix} \dfrac{3}{5}x^{5/3} \end {bmatrix} ^1_0$

Area = $\dfrac{3}{5}$

Then:

$\overline x = \dfrac{1}{A} \int^b_a x (f(x) -g(x) ) \ dx$

$\overline x = \dfrac{5}{3} \int^1_0 x (x^{2/3} -0 ) \ dx$

$\overline x = \dfrac{5}{3} \int^1_0 x^{5/3} \ dx$

$\overline x = \dfrac{5}{3} \ [\dfrac{3}{8}x^{8/3}]^1_0$

$\overline x = \dfrac{5}{3} \times \dfrac{3}{8}$

$\overline x = \dfrac{5}{8}$

Similarly;

$\overline y = \dfrac{1}{A} \int^b_a \dfrac{1}{2} \begin{bmatrix} (f(x)^)2 - (g(x))^2 \end {bmatrix} \ dx$

$\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (f(x^{2/3})^2 -0 \end {bmatrix} \ dx$

$\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (x^{4/3} ) \end {bmatrix} \ dx$

$\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{1}{2} (x^{7/3} ) \times \dfrac{3}{7} \end {bmatrix} ^1_0$

$\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{3}{14} (x^{7/3} ) \end {bmatrix} ^1_0$

$\overline y = (\dfrac{5}{3} \times \dfrac{3}{14} )$

$\overline y = \dfrac{5}{14}$

Thus; $\mathbf{(\overline x , \overline y ) = (\dfrac{5}{8}, \dfrac{5}{14})}$

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3 years ago

70% of kids who visit a doctor have a fever, and 40% of kids who visit a doctor have a sore throat. If the probability that a ki

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Answer: 21%

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