There are 10 seniors in the class, from which 4 should be chosen by the teacher. The order of the chosen students does not matter. This means that we speak of combinations. THe equation for calculating the number of possible combinations is:
C=N!/R!(N-R), where N is the total number of objects and R is the number of objects we select from the N
In our case, N=10, R=4.
C= 10!/4!*6!=10*9*8*7*6!/6!*4*3*2*1=<span>10*9*8*7/24=5040/24=210
There are 210 different ways for the teacher to choose 4 seniors in no particular order.</span>
Yes, you are correct, it is A!
Recall the pencil line test, which is where you go across the x axis (the graph horizontally) and see if the pencil touches any two points at the same time. If it does, then the graph is not a function.
Point being: since question a has a bunch of y values on top of one x value, the pencil would inevitably touch multiple at the same time, hence why it is easy to tell that it is not a function! Hope this helps :)
Answer:
<em>For part one...</em>
<em><u>you will multiply 4.5 by 3 to get 13.5 . </u></em>
<em>For part two,</em>
<u><em> you will multiply 3m by 4 to get 12.</em></u>
<u><em></em></u>
<em> (: </em><em><u>I hope this helps! BRAINLIEST is appreciated to get to virtuoso</u></em><em> :)</em>
Combine like terms
2m and -4m are like terms while 3m^2 isnt. So, leave 3m^2 as it is and combine the other set. 2m-4m = (-2m). Therefore, your answer should be 3m^2 - 2m
