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umka21 [38]
2 years ago
15

A portrait without its frame has a height two times it’s width (w) The width of the frame is 3 inches on all sides. What is the

area of the portrait and the frame? simplify your answer
Mathematics
1 answer:
aliina [53]2 years ago
6 0

Answer:I'm guessing 9×6? 54?

Step-by-step explanation:

You might be interested in
To find an equation for the line with slope -3 that passes through the point ( 4, 3 ), Dana wrote the following steps. Is he cor
Makovka662 [10]

Answer:

<h3>y=-3x+15</h3>

Step-by-step explanation:

m=-3\\\\(4,3)=(x_1,y_1)\\\\

Substitute values into point slope form

y-y_1=m(x-x_1)\\\\y -3=-3(x -4)\\\\y-3=-3x +12\\\\y=-3x+12+3\\\\y=-3x+15

3 0
2 years ago
A researcher was interested in comparing the resting pulse rates of people who exercise regularly and people who do not exercise
DiKsa [7]

Answer:

We Reject H₀ if t calculated > t tabulated

But in this case,

0.83 is not greater than 2.056

Therefore, we failed to reject H₀

There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.

Step-by-step explanation:

Refer to the attached data.

The Null and Alternate hypothesis is given by

Null hypotheses = H₀: μ₁ = μ₂

Alternate hypotheses = H₁: μ₁ ≠ μ₂

The test statistic is given by

$ t = \frac{\bar{x}_1  - \bar{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }  $

Where \bar{x}_1 is the sample mean of people who do not exercise regularly.

Where \bar{x}_2 is the sample mean of people who do exercise regularly.

Where s_1 is the sample standard deviation of people who do not exercise regularly.

Where s_2 is the sample standard deviation of people who do exercise regularly.

Where n_1 is the sample size of people who do not exercise regularly.

Where n_2 is the sample size of people who do exercise regularly.

$ t = \frac{72.7  - 69.7}{\sqrt{\frac{10.9^2}{16} + \frac{8.2^2}{12} } }  $

t = 0.83

The given level of significance is

1 - 0.95 = 0.05

The degree of freedom is

df = 16 + 12 - 2 = 26

From the t-table, df = 26 and significance level 0.05,

t = 2.056 (two-tailed)

Conclusion:

We Reject H₀ if t calculated > t tabulated

But in this case,

0.83 is not greater than 2.056

Therefore, We failed to reject H₀

There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.

4 0
3 years ago
Solve the compound inequality |3x-9|≤15 and |2x-3|≥5. Give answer in interval notation.
laila [671]

Answer:

The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is  (-∞,2] ∪ [8,∞)

Step-by-step explanation:

When solving absolute value inequalities, there are two cases to consider.

Case 1: The expression within the absolute value symbols is positive.

Case 2: The expression within the absolute value symbols is negative.

The solution is the intersection of the solutions of these two cases.

In other words, for any real numbers a and b,

  • if |a|> b then a>b or a<-b
  • if |a|< b then a<b or a>-b

So, being |3x-9|≤15

Solving: 3x-9 ≤ 15

3x ≤15 + 9

3x ≤24

x ≤24÷3

x≤8

or 3x-9 ≥ -15

3x ≥-15 +9

3x ≥-6

x ≥ (-6)÷3

x ≥ -2

The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]

So, being |2x-3|≥5

Solving: 2x-3 ≥ 5

2x ≥ 5 + 3

2x ≥8

x ≥8÷2

x≥8

or 2x-3 ≤ -5

2x ≤-5 +3

2x ≤-2

x ≤ (-2)÷2

x ≤ -2

Expressing the solution as an interval: (-∞,2] ∪ [8,∞)

6 0
3 years ago
What is the solution for tgx &gt;=0?
ddd [48]

well, what variable are you solving for? like if you're solving for x, it would be:

tg is greater than or equal to 0x

7 0
2 years ago
restaurant serves three types of omelettes. Surveys were taken of the last two days of orders and are displayed in the table bel
Ede4ka [16]

Answer:

The answer is 120

Step-by-step explanation:

Hope it helps

4 0
3 years ago
Read 2 more answers
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