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3 years ago

Mark simplified 3/5 divided by 5/8; his work is shown below. Identist where he made his error.

Mathematics

1 answer:

dolphi86 [110]3 years ago

4 0

Answer:

Mark forgot to multiply 5 · 5, so he ended up with 5 in the denominator instead of 5 · 5 = 25

Step-by-step explanation:

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At Bayside High School, 55% of the student body are boys. Thirty-five percent of the boys are on honor roll, and 40% of girls ar

iris [78.8K]

Answer:

37%

Step-by-step explanation:

35% of 55% is equal to the percent of boys on honor roll in the student body.

100 - 55 = 45%, which is the percent of girls in the student body.

40% of 45% is equal to the percent of girls on honor roll in the student body.

35% * 55% = 19.25%

40% * 45% = 18%

Adding them up, we get:

19.25 + 18 = 37.25%

Round it to the nearest percent.

37.25 --> 37%

Rounded to the nearest percent, 37% of the student body is on honor roll.

7 0

3 years ago

Solve for r. 1,2r-3=3(4-3,2r)

Helen [10]

Answer:

0.68865278

Step-by-step explanation:

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3 years ago

Solve the linear programming problem. Minimize and maximize Upper P equals negative 20 x plus 30 y Subject to 2 x plus 3 y great

Alika [10]

Answer:

Maximum = 540 at (6,14)

Minimum = 300 at (0,10) or (12,2).

Step-by-step explanation:

The given linear programming problem is

Minimize and maximize: P = 20x + 30y

Subject to constraint,

$2x+3y\ge 30$ .... (1)

$2x+y\le 26$ .... (2)

$-2x+3y\le 30$ .... (3)

$x,y\geq 0$

The related equation of given inequalities are

$2x+3y=30$

$2x+y=26$

$-2x+3y=30$

Table of values are:

For inequality (1).

x y

0 10

15 0

For inequality (2).

x y

0 26

13 0

For inequality (3).

x y

0 10

15 0

Pot these ordered pairs on a coordinate plane and connect them draw the corresponding related line.

Check each inequality by (0,0).

$2(0)+3(0)\ge 30\Rightarrow 0\ge 30$ False

$2(0)+(0)\le 26\Rightarrow 0\le 26$ True

$-2(0)+3(0)\le 30\Rightarrow 0\le 30$ True

It means (0,0) is included in the shaded region of inequality (2) and (3), and (0,0) is not included in the shaded region of inequality (1).

From the below graph it is clear that the vertices of feasible region are (0,10), (6,14) and (12,2).

Calculate the values of objective function on vertices of feasible region.

Point P = 20x + 30y

(0,10) P = 20(0) + 30(10) = 300

(6,14) P = 20(6) + 30(14) = 540

(12,2) P = 20(12) + 30(2) = 300

It means objective function is maximum at (6,14) and minimum at (0,10) or (12,2).

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3 years ago

Chuck E Cheese charges for the number of hours you rent the party room and the number of

e-lub [12.9K]

Answer:

Step-by-step explanation:

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3 years ago

Solve the system using substitution: x = -4y and x + 5y = 2<br> Please and thank you.

Novay_Z [31]

Answer:

x = - 8, y = 2

Step-by-step explanation:

$x = - 4y......(1) \\ x + 5y = 2....(2) \\ plug \: x = - 4y \: in \: equation \: (2) \\ - 4y + 5y = 2 \\ y = 2 \\ plug \: y = 2 \: in \: equation \: (1) \\ x = - 4(2) \\ x = - 8\\$

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3 years ago