Answer:
x=-15
Step-by-step explanation:
50=-10(x+10)
Distribute 10: 50=-10x-100
Add 100 to both sides: 100+50=-10x-100+100
150=-10x
Simplify: 150/-10=-10x/-10
x=-15
Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
.
The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:


Z = 1.71
Z = 1.71 has a p-value of 0.9564.
1 - 0.9564 = 0.0436.
0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
More can be learned about the normal distribution at brainly.com/question/24663213
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Answer:
log_3(2x+15)=2 and log_4(-20x+4)=3
Step-by-step explanation:
Plug it in and see!
Answer:
25
+ 30z³ + 29z² + 12z + 4
Step-by-step explanation:
(5z² + 3z + 2)²
= (5z² + 3z + 2)(5z² + 3z + 2)
Each term in the second factor is multiplied by each term in the first factor, that is
5z²(5z² + 3z + 2) + 3z(5z² + 3z + 2) + 2(5z² + 3z + 2) ← distribute parenthesis
= 25
+ 15z³ + 10z² + 15z³ + 9z² + 6z + 10z² + 6z + 4 ← collect like terms
= 25
+ 30z³ + 29z² + 12z + 4
Answer:
<em>(B). - 3 ≤ x < 1 </em>
Step-by-step explanation:
Given expression is defined for
1). x + 3 ≥ 0 ⇒ x ≥ - 3
and
2). 1 - x > 0 ⇒ x < 1
<em>- 3 ≤ x < 1</em>