True because it is used to collect information on data tables and other things.
F(x) = x²-4x-5, quadratic function,
Domain (the values if x) is all real numbers.
To find range we should draw a graph or to write an equation in vertex form.
f(x) = x²-4x+4-4-5
f(x) = (x-2)²-9
Point (-2,-9) is the vertex of the parabola, and it is a minimum because a parabola has positive sign in front of x², so it is looking up. Minimum value of y =-9
Range(the values of y) is [-9, ∞)
Answer : 4.5 × 10⁴ square inches can be washed per hour.
Step-by-step explanation :
As we are given that an area can be washed at a rate of 4,900 cm²/min. Now we have to determine the square inches can be washed per hour.
Given conversions are:
1 cm = 0.39 in and 1 hr = 60 min
As, 1 cm² = (0.39)² in² and 1 min = 1/60 hr
So, 
Now we have to determine the square inches can be washed per hour.
As,
So, 
Therefore, 4.5 × 10⁴ square inches can be washed per hour.
Answer:
Equation: 6f = 5
Result: 6/5 cup of flour is needed for each batch of bread
Step-by-step explanation:
Given
6 cups of flour makes 5 batches of bread
Required
His much flour is needed for each batch.
Let f represent a cup of flour.
The statement "total of 6 cups of flour to make 5 batches of bread." means that
f + f + f + f + f + f = 5 batches of bread
f * 6 = 5
6f = 5
The above equation will give the number of cup needed for 1 batch of bread.
To do that, we simply divide both sides by 5
6f/5 = 5/5
6f/5 = 1
Hence,
The equation is represented by: 6f = 5
And the result is: 6/5 cup of flour is needed for each batch of bread
Answer:
Q1. x= 18, y=59
Q2. m∠J= 56°
Step-by-step explanation:
Q1. (3x +5)°= y° (base ∠s of isos. △)
y= 3x +5 -----(1)
(3x +5)° +y° +(4x -10)°= 180° (∠ sum of △)
3x +5 +y +4x -10= 180
7x +y -5= 180
7x +y= 180 +5
7x +y= 185 -----(2)
Substitute (1) into (2):
7x +3x +5= 185
10x= 185 -5
10x= 180
x= 180 ÷10
x= 18
Substitute x= 18 into (1):
y= 3(18) +5
y= 59
Q2. (5x -13)°= (3x +17)° (base ∠s of isos. △)
5x -13= 3x +17
5x -3x= 17 +13
2x= 30
x= 30 ÷2
x= 15
∠LKJ
= 3(15) +17
= 62°
∠KLJ= 62° (base ∠s of isos. △)
m∠J
= 180° -62° -62° (∠ sum of △JKL)
= 56°
