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Dovator [93]
3 years ago
10

140% out of what gives 56

Mathematics
2 answers:
julia-pushkina [17]3 years ago
6 0
<span>140 / 100 * x = 56

140/100 = 1.4

1.4x = 56

1.4x/1.4 = 56/1.4

x= 40

Answer: x = 40</span>
Verizon [17]3 years ago
4 0


140 / 100 * X = 56

X = 56 * 100 / 140 = 5600 / 140 = 40

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The system of equations below form a line and a parabola. Select all possible solutions to this system from the answer choices b
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Answer:

no answer choices shown but solution

would be [-2.8, -∞] and [2.83, ∞]

Step-by-step explanation:

5 0
2 years ago
A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st
maxonik [38]

Answer:

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

p_v =2*P(z>1.413)=0.158  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

Step-by-step explanation:

Data given and notation  

\bar X=5.0611 represent the sample mean

\sigma=0.2803 represent the population standard deviation for the sample  

n=42 sample size  

\mu_o =5 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 5, the system of hypothesis would be:  

Null hypothesis:\mu = 5  

Alternative hypothesis:\mu \neq 5  

If we analyze the size for the sample is > 30 but and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>1.413)=0.158  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

8 0
3 years ago
So I know the answer for 8 is 2.24, but I'm not sure how to get that!!
Furkat [3]
Multiply 15 and 24 then divide that answer by 11.2.
8 0
3 years ago
I need to know<br> give 20 points to who answers this right.
NISA [10]

Step-by-step explanation:

I believe it's 16 1/2. I just used MathPapa lol.

5 0
2 years ago
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