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Katyanochek1 [597]
3 years ago
11

Please show your work

Mathematics
1 answer:
Andrei [34K]3 years ago
5 0

Answer:

a = 9

Step-by-step explanation:

a^2 = 41^2 - 40^2

a^2 = 1681-1600 = 81

a = 9

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How do you do this question?
vivado [14]

Answer:

-1

Step-by-step explanation:

dy/dt = y² − 1 = (y + 1) (y − 1)

At t = 0, y = 0, and dy/dt = -1.  Therefore, y is initially decreasing.

As y decreases, dy/dt increases.  When y = -1, dy/dt = 0 and changes signs from negative to positive.

As y increases above -1, dy/dt again becomes negative.  So y continues to approach -1 as t approaches infinity.

6 0
3 years ago
Solving these quadratics for x using complete the square 3x^2-4x-1=0. Show your work.
UkoKoshka [18]
Answer: x = (sqrt(7) + 2)/3 and
x = ( – sqrt(7) + 2)/3

Explanation:

3x^2 - 4x - 1 = 0

Divide both sides by 3:

3x^2/3 - 4/3x - 1/3 = 0/3
x^2 - 4/3x - 1/3 = 0
x^2 - 4/3x = 1/3
x^2 - 4/3x + (2/3)^2 = 1/3 + (2/3)^2
(x - 2/3)^2 = 1/3 + 4/9
(x - 2/3)^2 = 7/9

Sqrt both sides:

x - 2/3 = sqrt (7/9)
x - 2/3 = |sqrt(7)/3|

Set x -2/3 = sqrt(7)/3

=> x = (sqrt(7) + 2)/3

Set x - 2/3 = - sqrt(7)/3

=> x = ( - sqrt(7) + 2)/3
6 0
3 years ago
Rani, Anita, Jassi and Zoyz are each given a piece of wire of the same length. They bend the wire into different shapes as shown
LenKa [72]

Answer:

Saw this question before. The answer is Anita' square.

Square has only four sides while the others more than four so make sense for the square to have longer sides

3 0
3 years ago
Please help!! Free brainliest!!
sergejj [24]

Answer:

The ending bank balance would be $260.89

Step-by-step explanation:

210.84 - 40.00

170.84

170.84 + 90.05

260.89

6 0
3 years ago
Read 2 more answers
Determine the probability of selecting a two-child family with one boy and one girl assuming boys and girls are equally likely
Fittoniya [83]

Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.

For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • Two children, hence n = 2.
  • Equally as likely to be a boy or a girl, hence p = 0.5.

The probability of one of each is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.5)^{1}.(0.5)^{1} = 0.5

0.5 = 50% probability of selecting a two-child family with one boy and one girl.

A similar problem is given at brainly.com/question/24863377

3 0
3 years ago
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