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Scrat [10]
3 years ago
11

Lisa sold $75 worth of play tickets.Adult tickets cost $4 each and children’s ticket cost $4 each.How many children’s tickets co

uld she have sold?Is there more than one answer
Mathematics
1 answer:
Helga [31]3 years ago
3 0
Yes, there are many possible answers. An equation that can model your situation is:
4a+4b=75, with a being the amount of adult tickets sold, and b being the amount of children’s tickets sold.
Because both tickets cost 4 dollars, you would multiply the amount of tickets sold, by the price (in dollars) of the ticket.
So, you can find possible answers by substituting the amount of adult tickets sold. Say, 4 adults bought tickets. You could then substitute a for 4. So the equation would look like this.
4(4)+4b=75
16 + 4b = 75
4b = 75 - 16
4b = 59
Divide each side by four
B = 14.75

The reason you got a decimal number is because 75 cannot be divided by 4 evenly. So, in this context, you could say that 15 children bought tickets. One child had an issue, and Lisa gave them a 25% discount. This would explain why there are only 75 dollars worth in tickets. I hope I helped, this is my first question I have ever answered so I’m not entirely sure if this was helpful or not. Hope you figure this out!
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8 0
2 years ago
. Imagine a game of 3 players where exactly one player wins in the end and all players have equal chances of being the winner. T
lbvjy [14]

Answer:

5/9

Step-by-step explanation:

Number of players = 3

number of times game is repeated = 4

P( any person wins a game ) = 1/3

P ( any person does not win a game ) = 1 - 1/3 = 2/3

P ( any person wins no game in 4 attempts ) = ( 2/3 )^4 = 16/81

<em>Note : each player has equal chance of winning </em>

<u>Find the probability that there is at least one person who wins no games </u>

lets represent the probability of each player not wining a game with alphabet A

A1 = player 1 wins no game

A2 = player 2 wins no game

A3 = players 3 wins no game

Applying the inclusion-exclusion formula

<em>P( A1 ∪ A2 U A3 )</em><em> = P(A1 ) + P(A2) + P(A3) - P( A1 ∩ A2 ) - P( A2 ∩ A3 ) - P( A1            ∩ A3 )  + P( A1 ∩ A2 ∩ A3 ) </em>

where

P( A1 ∩ A2 ) = P( A1 wins all games )

P ( A1 wins all games in 4 attempts ) = ( 1/3 )^4 = 1/81

P( A1 ∩ A2 ∩ A3 ) = P ( no players wins any game in 4 attempts ) = 0

Hence

P( A1 ∪ A2 U A3 ) = 16/81 + 16/81 + 16/81 - 1/81 - 1/81 - 1/81 - 0 = 5/9

6 0
3 years ago
Please help me with this question
jeyben [28]

Answer:

37

add all of them together then divide it by two

4 0
3 years ago
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3 years ago
An 18 pound turkey cooks for 4.5 hours. How long will it take for a 12 pound turkey to cook?
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Answer:

3 hours

Step-by-step explanation:

We can solve using ratios

18 lbs            12 lbs

------------ = --------------

4.5 hrs          x hours

Using cross products

18x = 12 * 4.5

18x = 54

Divide by 18

18x/18 = 54/18

x=3

6 0
3 years ago
Read 2 more answers
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